Question

Calculate the deflection at point C of a beanm subjected to uniformly distributed load w 275 N/mm on span AB and point load P-10 kN at C. Assume that L = 5 m and EI = 1.50 × 107 N·m2

Answer 1

Answer:

Deflection at point C = 0.151 m

Explanation:

Central deflection due to uniformly distributed load w for simply supported beam

         $\delta =\frac{5wl^4}{384EI}$

Central deflection due to point load P for simply supported beam

         $\delta =\frac{Pl^3}{48EI}$

Here deflection

          $\delta =\frac{5wl^4}{384EI}+\frac{Pl^3}{48EI}=\frac{5\times 275\times 10^3\times 5^4}{384\times 1.5\times 10^7}+\frac{10\times 10^3\times 5^3}{48\times 1.5\times 10^7}\\\\\delta =0.149 + 1.74\times 10^{-3}=0.151m$

Deflection at point C = 0.151 m