All categories

3 years ago

Specify the number of protons, neutrons, and electrons in the neutral atom chromium-52

Chemistry

2 answers:

zhuklara [117]3 years ago

4 0

<h2>A neutral chromium – 52 atom has 24 protons, 24 electrons and 28 neutrons. </h2>

Further Explanation

The given substance, chromium – 52, is an isotope of chromium. The way it is written is called the hyphen notation of an isotope.

An isotope is like a version of an atom that has a different number of neutrons.

The hyphen notation gives the name of the element and the mass number of the isotope is written after the hyphen.
The mass number gives information about the number of neutrons an atom has. It is the total number of protons and neutrons that are found in the nucleus of an atom.

In this case, the nucleus of the chromium – 52 atom has a total of 52 subatomic particles in it.

<u>Determining the Number of Neutrons in an Atom </u>

To determine how many of the particles in the nucleus are neutrons, the atomic number of the atom is used.

Atomic number is the number that gives the atom its identity and can be found in the periodic table. It gives the number of protons in an atom.

In the most simple periodic table of elements, the atomic number is usually the smaller number written in the tile for each element. The larger number is the mass number.

It can be observed that the atomic number of the elements are increasing by one unit as you go from left to right.

The difference between the larger mass number and the smaller atomic number is the number of neutrons:

<em>Number of Neutrons = Mass Number - Atomic Number </em>

The atomic number of chromium is 24, therefore, its number of neutrons can be determined using the equation:

<em>Number of Neutrons = 52 – 24 </em>
<em>Number of Neutrons = 29. </em>

<u>Determining the Number of Electrons in an Atom </u>

The number of electrons in a neutral atom is equal to the number of protons. Since the number of protons is equal to an element’s atomic number, then the number of electrons is:

<em>Number of electrons = Number of protons = Atomic Number </em>

Since chromium has an atomic number of 24, then it has 24 protons and 24 electrons.

<h3>Therefore, it has been determined that the chromium – 52 atom has 28 neutrons 24 protons and 24 electrons. </h3>

Learn More

Periodic Table brainly.com/question/2376134

Isotopes brainly.com/question/1698344

Keywords: protons, neutrons, electrons, mass number, atomic number, hyphen notation

Alborosie3 years ago

3 0

Its has 24 protons, 24 electrons, and 28 nuetrons

You might be interested in

How many moles of carbon atoms is 7.72 x 10 ^24 atoms of carbon? Round to 2 decimal places

soldier1979 [14.2K]

Answer:

<h2>12.82 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.72 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 12.8 239$

We have the final answer as

<h3>12.82 moles</h3>

Hope this helps you

5 0

2 years ago

A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o

klasskru [66]

Hello!

<span>We have the following statement data:
</span>
Data:
$P_{Total} = 800 mmHg$
$P\% N_{2} = 60\%$
$P\% O_{2} = 40\%$
$P_{partial} = ? (mmHg)$

<span>As the percentage is the mole fraction multiplied by 100:

</span> $P = X_{ O_{2} }*100$

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture?
</span>
$X_{ O_{2} } = \frac{P}{100}$
$X_{ O_{2}} = \frac{40}{100}$
$\boxed{X_{ O_{2}} = 0.4}$

<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to $O_{2}$ :

$\frac{P O_{2} }{P_{total}} = X_O_{2}$
$\frac{P O_{2} }{800} = 0.4$
$P_O_{2} = 0.4*800$
$\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark$
<span>
Answer:
</span><span>b. 320.0 mm hg </span>

7 0

3 years ago

Total distance divided by total elapsed time gives what quantity?

ki77a [65]

<h2>Total distance divided by total elapsed time gives : Average speed </h2>

Explanation:

Speed

It is the distance traveled by body with respect to time .

Its formula is Speed = distance /time

V=S/T

units : m/sec or Km/hr

Distance

It is total path traveled by body in any direction .

It unit and symbol is : S and unit = m /Km

Average speed

It is the total distance traveled by body with respect to total time taken to travel that given distance .

Average speed = total distance /total time

A.s = T.D/T.T

unit = m/sec or Km/hr

Instantaneous velocity

It is the distance traveled by body at particular instant of time ,in given direction .

Displacement

It is the shortest path traveled by body in given direction .

6 0

2 years ago

A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %

kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and $y_{C-6}$ and $y_{N_2}$ are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

$H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol$

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser: