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Nady [450]
3 years ago
9

A 35.0-kg dolphin decelerates from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to

slow the first dolphin if it was moving horizontally? (The gravitational force is balanced by the buoyant force of the water.)
Physics
1 answer:
Stels [109]3 years ago
6 0

Answer:

68.5N

Explanation:

When the dolphin decelerates from 12m/s to 7.5 m/s within 2.3s. Then its acceleration is:

a = \frac{\Delta v}{\Delta t} = \frac{7.5 - 12}{2.3} = -1.96 m/s^2

The dolphin has a mass of 35kg, according to the Newton's 2nd law, the force exerted on it must be:

F = ma = 35*1.96 = 68.5 N

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If 68 W of power is produced in 18 seconds, how much work is done?
spayn [35]

Answer: 1224 joules

Explanation:

Given variables are:

Power (p) = 68 W

Time taken (t) = 18 seconds

work done (w) = ?

Recall that power is the rate of work done per unit time i.e Power is obtained by dividing the work done by the time taken.

Hence, Power = work / time

Make work the subject formula

work = power x time

work = 68 watts x 18 seconds

work = 1224 joules

Thus, 1224 joules of work is done.

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A 10kg rock is pushed off the edge of a bridge 50 meters above the ground . What was the kinetic energy of the rock before it be
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3 years ago
A 2.0-mm-long, 1.0-mmmm-diameter wire has a variable resistivity given by rho(x)=(2.5×10−6)[1+(x1.0m)2]Ωmrho(x)=(2.5×10−6)[1+(x1
Tresset [83]

Answer:

1.144 A

Explanation:

given that;

the length of the wire = 2.0 mm

the diameter of the wire = 1.0 mm

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Taking the integral of both sides;we have:

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R = 14.863 Ω

Since V = IR

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I = \frac{17}{14.863}

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8 0
3 years ago
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Law Incorporation [45]

Answer:

1 is c 2 is a and 3 is b hope that helped!

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