Answer:
(a). The magnitude of the acceleration of the proton is 
(b). The initial peed of the protion is 
(c). The time is
.
Explanation:
Given that,
Electric field 
Time = 5.0 sec
Distance 7.00 cm
(a). We need to calculate the acceleration
Using formula of force



Where, E = electric field
m = mass of proton
q = charge of proton
Put the value into the formula


The magnitude of the acceleration of the proton is 
(b). We need to calculate the initial peed
Using equation of motion

Where, s = distance
Put the value into the formula




The initial peed of the protion is 
(c). We need to calculate the time interval over which the proton comes to rest
Using formula

Where, u = initial velocity
a = acceleration
Put the value into the formula


Hence, (a). The magnitude of the acceleration of the proton is 
(b). The initial peed of the protion is 
(c). The time is
.
Answer:
D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward
If you're careful, you ought to be able to observe ANY of these properties
without any effect on the substance:
Absorption, albedo, angular momentum, area, color, concentration,
density, elasticity, electric charge, electrical conductivity, flow rate,
electrical impedance, electric potential, fluidity, length, location, mass,
luminance, luminescence, luster, magnetic field, momentum, opacity,
permeability, permittivity, plasticity, pressure, radiance, solubility, spin,
specific heat, resistivity, reflectivity, refractive index, temperature,
thermal conductivity, velocity, viscosity, or volume.
Answer:
vertical velocity = 33.55 m/s
Explanation:
sin (34) = v/60
sin (34) x 60 = v
33.55 m/s = v