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DerKrebs [107]
3 years ago
7

Which statement is correct? (a) Net force causes motion. (b) Net force causes change in motion. Explain your answer and give an

example.
Physics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

(b) Net force causes change in motion.

Explanation:

There can be a motion even if there is no net force acting on an object.

It can be justified by giving an example:- when object is  moving at constant speed then it has no net force and still is in motion.

If there is a net force acting, then the object will accelerate and this will cause change in motion.

The change in motion can be change in direction of motion, change in speed of motion.

For example when an object is moving in east direction if someone accelerate it this will result in change in motion or change in speed and after some time the net force is applies in the north direction then the object will move in the north direction which proves that the net force also causes change in direction.

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Como estan formados los musculos?
VikaD [51]

Answer:

Explanation: El músculo esquelético está formado por fibras musculares, rodeadas de una capa de tejido conjuntivo, denominada endomisio. Las fibras se reúnen en fascículos primarios, que también están rodeados por otra capa de tejido conjuntivo, esta vez, más grueso, denominada perimisio.

3 0
2 years ago
Read 2 more answers
11. A plow pushes 100 kg of snow with 300 N of force. How much is the pile of snow<br> accelerated?
Fed [463]

Answer:

Explanation:

This is an application of Newton's second Law.

Formula

F = m * a

F = 300 N

m = 100 kg

a = ?

F = m * a

300N = 100 kg * a            Divide by 100

300N/100kg = a

a = 3 m/sec^2

3 0
2 years ago
In a historical movie, two knights on horseback start from rest 86 m apart and ride directly toward each other to do battle. Sir
Harlamova29_29 [7]

Answer:

Relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.

Explanation:

Let the distance covered by Sir George be S_{1}

and the distance covered by Sir Alfred be S_{2}

Since the knights collide, hence they must have traveled for the same amount of time just before collision

From one of the equations of motion for linear motion

S = ut + \frac{1}{2}at^{2}

Where S is the distance traveled

u is the initial velocity

a is the acceleration

and t is the time

For Sir George,

S = S_{1}

u = 0 m/s (Since they start from rest)

a =0.21 m/s²

Hence,

S = ut + \frac{1}{2}at^{2} becomes

S_{1}  = (0)t + \frac{1}{2}(0.21)t^{2}\\S_{1}  = 0.105 t^{2}\\

t^{2} = \frac{S_{1}}{0.105}

Now, for Sir Alfred

S = S_{2}

u = 0 m/s (Since they start from rest)

a =0.26 m/s²

Hence,

S = ut + \frac{1}{2}at^{2} becomes

S_{2}  = (0)t + \frac{1}{2}(0.26)t^{2}\\S_{2}  = 0.13 t^{2}\\

t^{2} = \frac{S_{2}}{0.13}

Since, they traveled for the same time, t just before collision, we can write

\frac{S_{1}}{0.105}= \frac{S_{2}}{0.13}

Since, the two nights are 86 m apart, that is, the sum of the distances covered by the knights just before collision is 86 m. Then we can write that

S_{1} + S_{2} = 86 m

Then, S_{2} = 86 - S_{1}

Then,

\frac{S_{1}}{0.105}= \frac{S_{2}}{0.13} becomes

\frac{S_{1}}{0.105}= \frac{86 -S_{1}}{0.13}

0.13{S_{1}}= 0.105({86 -S_{1}})\\0.13{S_{1}}= 9.03 - 0.105S_{1}}\\0.13{S_{1}} + 0.105S_{1}}= 9.03 \\0.235{S_{1}} = 9.03\\{S_{1}} =\frac{9.03}{0.235}

S_{1} = 38.43 m

∴ Sir George covered a distance of 38.43 m just before collision.

Hence, relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.

6 0
2 years ago
What is the wavelength of a wave that is traveling at 343 m/s with a frequency of 1000 Hz
ZanzabumX [31]

Answer:

343 \div 1000 = 0.343

wavelength is equivalent to the velocity divided by the frequency

3 0
2 years ago
A mass is oscillating up and down on a spring. In the above graph of
melomori [17]

Answer:

<em>Amplitude= 8 m</em>

Explanation:

<u>The Amplitude of a Wave</u>

Sinusoidal Function  refers to a mathematical curve with a smooth and periodic oscillation. Its name comes from the sine function and is characterized by the amplitude or the maximum displacement or distance moved by a point on a vibrating body measured from its equilibrium position.

To calculate the amplitude from a graph, we measure the maximum point and the minimum point the wave reaches. Then we subtract both values and divide the result by 2.

The shown wave in the figure has a maximum value of 8 m and a minimum value of -8 m. The distance from the maximum to the minimum is 8-(-8)= 16 m, thus the amplitude is 16/2= 8m.

Amplitude= 8 m

5 0
2 years ago
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