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GalinKa [24]
3 years ago
6

Before hanging new William Morris wallpaper in her bedroom, Brenda sanded the walls lightly to smooth out some irregularities on

the surface. The sanding block weighs 1.70 N and Brenda pushes on it with a force of 3.00 N at an angle of 30.0° with respect to the vertical, and angled toward the wall. What is the coefficient of kinetic friction between the wall and the block?

Physics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

1.0193

Explanation:

The concepts that we apply here is Frictional Force with a Force on the object with a angle.

We know that Frictional Force is equal to

F_f = \mu N

The force acts downward because the moving is upward, then from the image that I attached, the forve is equal to,

Fcos30° = 3N(cos30) = 2.6

In Y we have then

1.7N + f_x = 2.6

f_x = 1.529N

For the horizontal componentes we have that

N = (3N)sin30\°

N = 1.5 N

Using the first equation we have that

F_f = \mu N

1.529N = \mu 1.5 N

Re-arrange for \mu

\mu = 1.0193

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A toy car having mass m = 1.50 kg collides inelastically with a toy train of mass M = 3.60 kg. Before the collision, the toy tra
baherus [9]

Answer:

  v_{f} = 3,126 m / s

Explanation:

In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.

the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s

Before the crash

    p₀ = m v₁₀ + M v₂₀

After the inelastic shock

    p_{f}= m v_{1f} + M v_{2f}

    p₀ =  p_{f}

    m v₀ + M v₂₀ = m v_{1f}  + M v_{2f}

We cleared the end of the train

     M v_{2f} = m (v₁₀ - v1f) + M v₂₀

Let's calculate

     3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45

     v_{2f}  = (-3.9 + 8.82) /3.60

      v_{2f}  = 1.36 m / s

As we can see, this speed is lower than the speed of the car, so the two bodies are joined

set speed must be

      m v₁₀ + M v₂₀ = (m + M) v_{f}

      v_{f}  = (m v₁₀ + M v₂₀) / (m + M)

      v_{f}  = (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)

      v_{f} = 3,126 m / s

4 0
4 years ago
A 2000 kg car is driving at 5 m/s on wet asphalt, but then makes a turn on some ice and loses control. The driver applies brakes
lesya [120]

Answer:

10,000kgm/s

Explanation:

Since we not told what to look for, we can as well find the momentum of the car.

momentum = mas * velocity

Given

Mass of the car = 2000kg

velocity = 5m/s

Substitute into the formula

Momentum = 2000 * 5

Momentum = 10000kgm/s

Hence the momentum of the car is 10,000kgm/s

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3 years ago
A toaster uses 1500 W of power when connected to a voltage of 120 V. What is the resistance
iVinArrow [24]

AnswerThe current through a toaster connected to a 120-V source is 8.0 A. What power is given off by the toaster? p= 8.0 A : 120V (p=960 W Page 2 7. The resistance of an electric stove eleinent at operating temperature is 11 12.

Explanation:

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3 years ago
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Tanya [424]

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

<h3>Force exerted outside the wheel</h3>

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

  • Let the distance traveled by the load = 1.5 m
  • Let the radius of the wheel or position of the force = 0.45 m

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Learn more about angular momentum here: brainly.com/question/7538238

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ladessa [460]

Answer:

Explanation:

No entiendo

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