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Lyrx [107]
3 years ago
7

Wendy is using a poorly calibrated electronic balance to measure the mass of a crucible. Her technique in making the measurement

is very careful and she repeats it three times.What will likely characterize her measurements?
A) low accuracy and high precision

B) low accuracy and low precision

C) high accuracy and low precision

D) high accuracy and high precision
Chemistry
1 answer:
Nataly [62]3 years ago
4 0
B answer is b I repeat it’s b
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GIVING BRAINLIEST!! PLEASE HELP
LenaWriter [7]

Answer:

huh

Explanation:

8 0
3 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
How many moles of hypomanganous acid. H3 MnO4, are contained in 22.912 g?
gregori [183]

Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

6 0
3 years ago
Determine the number of grams in each of the quantities<br><br> 1.39.0 x 1024 molecules Cl2
STatiana [176]

Mass of Cl₂ : 164.01 g

<h3>Further explanation</h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol Cl₂ :

\tt n=\dfrac{N}{No}\\\\n=\dfrac{1.39.10^{24}}{6.02.10^{23}}\\\\n=2.31

mass Cl₂(MW=71 g/mol) :

\tt mass=mol\times MW\\\\mass=2.31\times 71=164.01

8 0
3 years ago
How many moles of h+ are associated with the acid h2so3 during neutralization?
Katena32 [7]

H2SO3 or sulfurous acid is actually a strong acid. We know for a fact that strong acids completely dissociate into its component ions in a solution, that is:

 

<span>H2SO3 -->  2H+  +  SO3-</span>

 

<span>So from the equation above, there are 2 moles of H+</span>

8 0
3 years ago
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