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Lyrx [107]
3 years ago
7

Wendy is using a poorly calibrated electronic balance to measure the mass of a crucible. Her technique in making the measurement

is very careful and she repeats it three times.What will likely characterize her measurements?
A) low accuracy and high precision

B) low accuracy and low precision

C) high accuracy and low precision

D) high accuracy and high precision
Chemistry
1 answer:
Nataly [62]3 years ago
4 0
B answer is b I repeat it’s b
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As stars get older, before they collapse, they throw off dust, heavy atoms and other materials an form a new
andre [41]

Answer:

B or D

Explanation:

.....I'm pretty sure I earned on some kids tv show

7 0
3 years ago
Read 2 more answers
I'd really appreciate help- this is due in around 8 hours :"D
Fed [463]

Answer:

  1. atomic #= 1
  • protons equals one
  • Number of neutrons equals to 0
  • number of electrons equal to 1
  • mass number equals to 1

2.

  • atomic number equals to 1
  • Protons equals to 1
  • number of neutrons equals to 0
  • number of electrons equals to 0 because the plus sign means that it loses an electron
  • mass number equals to 1

3.

  • atomic number 17
  • number of protons 17
  • number of neutrons 18
  • number for electrons 18 Because negative sign means It's an anion which means it gains an electron
  • mass number 35

4.

  • 12
  • 12
  • 12
  • 10 loses 2 its a cation
  • 24

5.

  • 47
  • 47
  • 108-47 = 61
  • 46 loses 1
  • 108

6.

  • 16
  • 16
  • 32-16 =16
  • 18 it gains 2 electrons
  • 32

there u go

7 0
3 years ago
Consider a 1260-kg automobile clocked by law-enforcement radar at a speed of 85.5 km/h. If the position of the car is known to w
-BARSIC- [3]
The expected speed is v = 85.5 km/h
 v = 85.5 km/h = (85.5 km/h)*(0.2778 (m/s)/(km/h)) = 23.75 m/s

If there is an uncertainty of 2 meters in measuring the position, then within a 1-second time interval:
The lower measurement for the speed is v₁ = 21.75 m/s,
The upper measurement for the speed is v₂ = 25.75 m/s.
The range of variation is
Δv = v₂ - v₁ = 4 m/s

The uncertainty in measuring the speed is
Δv/v = 4/23.75 = 0.1684 = 16.84%

Answer: 16.8%
3 0
3 years ago
PLEASE HELPPP. I'LL AWARD BRAINLIEST !!!!!
dsp73

Answer:

the properties of catalyst are

it remains unchanged after chemical reactions

it accelerate or deaccelerate the reaction without taking part in it

Explanation:

they are used to convert raw materials into useful one

catalyst are integral in making plastics

5 0
3 years ago
A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the
yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0
2 years ago
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