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Lyrx [107]
3 years ago
7

Wendy is using a poorly calibrated electronic balance to measure the mass of a crucible. Her technique in making the measurement

is very careful and she repeats it three times.What will likely characterize her measurements?
A) low accuracy and high precision

B) low accuracy and low precision

C) high accuracy and low precision

D) high accuracy and high precision
Chemistry
1 answer:
Nataly [62]3 years ago
4 0
B answer is b I repeat it’s b
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I have no idea on how to do this here is the question (For the following pairs of atoms, show how they transfer valence electron
Maru [420]

Answer:

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Explanation:

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3 years ago
A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is:
Gre4nikov [31]

Its magnifying power is: 4X 5X 9X 20X. A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is 9x. This answer has been confirmed as correct and helpful.

7 0
3 years ago
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Allena and Charissa were discussing whether Cl2 is an element or a compound. Allena said that it is an element because it has on
kobusy [5.1K]
Answer is: Allena is correct. It is an element because it is only made of chlorine atoms.
A chemical element bonded to an identical chemical element is not a chemical compound since it is made from only one element and not from two different elements. Chlorine is molecule, but not compound.
8 0
4 years ago
Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac
GalinKa [24]
<h2>a) The rate at which NO_2 is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen O_2 is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt} = 0.066 M/s

Rate in terms of disappearance of O_2 = -\frac{1d[O_2]}{dt}

Rate in terms of appearance of NO_2= \frac{1d[NO_2]}{2dt}

1. The rate of formation of NO_2

-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}

\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s

2. The rate of disappearance of O_2

-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}

-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0
3 years ago
If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Leviafan [203]

Answer:

V_{2} = 29.28\,L

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)

V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)

V_{2} = 29.28\,L

5 0
3 years ago
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