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3 years ago

I need help ASAP

Mathematics

1 answer:

marin [14]3 years ago

5 0

Answer:

what are your answer choices ? i can still help.

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Calculate the length of AB if A is the point (2,3) and B is the point (-2,0)

d1i1m1o1n [39]

Answer:

Formular for coordinate length:

$length = \sqrt{ {(x_{1} - x _{2} )}^{2} + {(y_{1} - y_{2})}^{2} }$

In considerance of coordinates given of A and B

$x _{1} \: \: is \: \: 2 \\ x_{2} \: \: is \: \: - 2 \\ y_{1} \: \: is \: \: 3 \\ y_{2} \: \: is \: \: 0$

therefore substitute:

$length = \sqrt{ { \{2 - ( - 2) \}}^{2} + {(3 - 0)}^{2} } \\ \\ = \sqrt{ {(2 + 2)}^{2} + {3}^{2} } \\ = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ \\ { \boxed{ \boxed{length \: \: is \: \: 5 \: units}}}$

5 0

3 years ago

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Which choices are equivalent to the quotient below?

scZoUnD [109]

Answer:

A, E and F

Step-by-step explanation:

All three of them equal root 5.

8 0

3 years ago

What’s 1 fourth of 1490

Kazeer [188]

1490/4 =372.5................

4 0

3 years ago

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago

To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

vovikov84 [41]

Answer:

use -9 to multiply the first equation

use -4 to multiply the second equation.

Step-by-step explanation:

5x-4y=28.....eqn (1)×-9

3x-9y=30....eqn(2)×-4

-45x+36y=-252

-(-12x+36y=-120)

therefore, -33x÷33 =-132÷-33

x=4.

substitute (x=4) in any of the equation. I'm just going to use eqn 1.

5x-4y=28

5(4)-4y=28

20-4y=28

-4y =28-20

-4y÷-4 = 8÷-4

y=-2

so, x=4, y=-2

Note: for proof of answers substitute the answers for x and y and see if you have the same result...e.g

5(4)-4(-2)=28.

6 0

3 years ago

Read 2 more answers