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GuDViN [60]
3 years ago
6

What is relative mass of an atom

Chemistry
1 answer:
kow [346]3 years ago
8 0

Answer:

Explanation:

The relative atomic mass of an element is a weighted average of the masses of the atoms of the isotopes - because if there is much more of one isotope then that will influence the average mass much more than the less abundant isotope will.

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Help me pls brainliest goes to first to answer
iris [78.8K]

Answer:

Answer: The solubility of B is high than the solubility of A.  

Explanation:

The solubility is defined as the amount of substance dissolved in a given amount of solvent. More the solute gets dissolved, high will be the solubility and less the solute dissolved, low will be the solubility.  

Mass of undissolved substance of substance A is more than Substance B at every temperature. This implies that less amount of solute gets dissolved in the given amount of solvent.

Therefore, B has high solubility than substance A.

3 0
3 years ago
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What elements are found in the compound represented in the diagram
DedPeter [7]
 hydrogen and carbon, hope that helped


3 0
3 years ago
What is the main difference between a generator and an electric motor? _______
garri49 [273]

Answer:

A generator produces electricity and an electric motor consumes electricity

4 0
3 years ago
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glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
The oxidation state of phosphorus is +3 in
IgorC [24]

Answer:

b) Phosphorus acid

Explanation:

To distinguish the type of acid of phosphorus with the oxidation state of +3, we need to be familiar with the chemical formula of each of the compounds:

    Orthophosphoric acid             H₃PO₄

    Phosphorus acid                       H₃PO₃

    Metaphosphoric acid               HPO₃

    Phyrophosphoric acid​               H₄P₂O₇

Now that we know the formula of the given compounds, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero:

Only phosphorus acid yielded an oxidation state of +3 for phosphorus in the compound.

  H₃PO₃:

   we know the oxidation state of H = +1

                                                          O = -2

         The oxidation state of P is unknown. We can express this as an equation:

                3(+1) + P + 3(-2) = 0

                    3 + P -6 = 0

                          P-3 = 0

                          P = +3

6 0
3 years ago
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