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katrin [286]
3 years ago
7

Problem 13.145 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS NOTE: This is a multi-part question. Once an answer is submitte

d, you will be unable to return to this part. A 100-ton tugboat is moving at 6 ft/s with a slack towing cable attached to a 100-ton barge that is at rest. The cable is being unwound from a drum on the tugboat at a constant rate of 5.4 ft/s and that rate is maintained after the cable becomes taut. Problem 13.145.a - Tugboat velocity Neglecting the resistance of the water, determine the velocity of the barge after the cable becomes taut. (You must provide an answer before moving to the next part.) The velocity of the TUGBOAT after the cable becomes taut is ft/s.

Physics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

Please see the attached picture for the complete answer.

Explanation:

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Assume the price of gasoline doubles tonight and remains at that price the next two years. The price elasticity of demand for ga
Serggg [28]

Answer:

more inelastic

Explanation:

Assume the price of gasoline doubles tonight and remains at that price for the next two years. The price elasticity of demand for gasoline measured tomorrow will be <u>more inelastic</u> when compared with the price elasticity of demand for gasoline measured two years from now.

Inelastic refers to the static quantity of a good or service when its price changes.

5 0
3 years ago
Mercury is 0.39 AU from the sun. What is its distance from the sun in kilometers?
qaws [65]

Answer:

0.39AU = 58344000 [km] or 58.500.000 [km]

Explanation:

This is a problem that consists simply in converting units:

AU = astronomic unit

1 [AU] = 1.496*10^{8} [km]\\0.39 [AU] = x\\\\Therefore\\x = \frac{0.39*1.496*10^{8} }{1} \\x = 58344000[km]

8 0
3 years ago
What is the value of vEp? Select One of the Following (a) 345 mph (b) -345 mph (c) 255 mph (d) 255 mph
serious [3.7K]

We're not completely sure what vEp stands for.

On Etsy, the "value of Eggs from pheasants" is $7.98 a dozen. Shipping is probably additional.

7 0
4 years ago
You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a
iogann1982 [59]

Answer:

a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°

Explanation:

Given the following ;

From the triangle sketch :

Base length = 50 yards

Angle of elevation = 72°

a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?

Using trigonometry :

The height of the blimp will be calculated using :

Tangent :

Tan θ = opposite / Adjacent

B.) How high above the ground is the blimp?

Using :

Tan θ = opposite / Adjacent

Θ = 72° ; adjacent = 52, opposite = height(h)

Tan 72° = h / 50

h = 3.0776835 * 50

h = 153.88 yds

C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?

1 yard = 3 Feets

153.88 yards = 3 * 153.88

= 461.65 feets

No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.

To make viewing possible, the angle of elevation should be:

50 yards is equivalent to (3 * 50) = 150 feets

Max imum Height of blimp = 150 Feets

From pythagoras ;

Tanθ = 150 Feets / 150 Feets

Tanθ = 1

θ = tan^-1(1)

θ = 45°

To make viewing advertisement possible, angle of elevation should not exceed 45°

d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°

5 0
3 years ago
Give v=120m/s north and t = 10.2, calculate the displacement
Sedbober [7]

Answer:

Displacement from the starting position is 1224m

Explanation:

The object is moving at 120 meters per second, it does this for 10.2 seconds. Use multiplication to find the answer.

120 \times 10.2 = 1224

4 0
3 years ago
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