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SSSSS [86.1K]
3 years ago
5

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with an acceleration of -

5.60 m/s2 for 4.20 s, making straight skid marks 62.4 m long ending at the tree. With what speed does the car then strike the tree
Physics
1 answer:
Zarrin [17]3 years ago
3 0
The equation for speed is s=d÷t the distance=62.4m and the time=4.20s so 62.4÷4.20= 14.857
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Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
Kazeer [188]

Answer:

a = 3.27 m/s²

T = 275 N

Explanation:

Given that:

Mass m₁ = 42.p0 kg

Mass m₂ = 21.0 kg

Consider both masses to be in a whole system, then:

The acceleration can be determined as:

(m_1+m_2)a = g(m_1-m_2)

Making acceleration the subject in the above formula;

a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}

a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}

a =\dfrac{9.8(21.0)}{(63.0)}

a =\dfrac{205.8}{(63.0)}

a = 3.27 m/s²

in the string, the tension is calculated using the formula:

T = \dfrac{2m_1m_2g}{(m_1+m_2)}

T = \dfrac{2(42)(21)(9.81)}{(42+21)}

T = \dfrac{17304.84}{63}

T = 274.68 N

T ≅ 275 N

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3 years ago
Complete the statement below with all that apply.
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Answer:

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Light-rail passenger trains that provide transportation within and between cities are capable of modest accelerations. The magni
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During the first phase of acceleration we have:
v o = 4 m/s;  t = 8 s; v = 13 m/s, a = ?
v = v o + a * t
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v = v o + a * t
v = 13 m/s + 1.125 m/s² * 16 s
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3 years ago
Does anyone know the answer
scoundrel [369]
No put false I am right
7 0
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