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Sergio039 [100]
3 years ago
15

Write a balanced equation for the reaction of Na₂S and CdSO₄. Express your answer as a chemical equation. Identify all of the ph

ases in your answer. Enter no reaction if no precipitate is formed.
Chemistry
1 answer:
Luba_88 [7]3 years ago
3 0

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced chemical reaction equation.

For example, Na_{2}S(aq) + CdSO_{4}(aq) \rightarrow Na_{2}SO_{4}(aq) + CdS(s)

Here, number of reactant molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

Number of product molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

As there are already equal number of atoms on both reactant and product side. Hence, the reaction equation is balanced.

Also, in this reaction both Na_{2}S and CdSO_{4} are present as aqueous solution. And, CdS is the precipitate that is formed as it is the insoluble solid that forms.

Na_{2}SO_{4} is present in aqueous state.

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A galvanic (voltaic) cell consists of an electrode composed of chromium in a 1.0 M chromium(III) ion solution and another electr
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Answer: The potential of the following electrochemical cell is 1.08 V.

Explanation:

E^0_(Cr^{3+}/Cr)=-0.74V[/tex]

E^0_(Cu^{2+}/Cu)=0.34V[/tex]

The element  with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

Here Cr undergoes oxidation by loss of electrons, thus act as anode. copper undergoes reduction by gain of electrons and thus act as cathode.

2Cr+3Cu^{2+}\rightarrow 2Cr^{3+}+3Cu

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials, when concentration is 1M.

E^0=E^0_{[Cu^{2+}/Ni]}- E^0_{[Cr^{3+}/Cr]}

E^0=0.34-(-0.74)=1.08V

Thus the potential of the following electrochemical cell is 1.08 V.

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