All categories

2 years ago

What would be the position of the centre of mass?

Physics

1 answer:

AnnyKZ [126]2 years ago

6 0

Answer: the average position of all the parts of the system, weighted according to their masses.

Explanation:

You might be interested in

Stick a fork into each end of the root vegetable as shown. The forks should be on the same side of the vegetable, and

zhuklara [117]

Answer:

Yes

Explanation:

There is a position that works better than this and that is switching the sides of the forks.

7 0

2 years ago

find formula for viscous force (F) acting on a sphere of radius (R) falling with velocity(V) through a medium of coetticient of

Angelina_Jolie [31]

Answer:

Here is my answer

Explanation:

8 0

3 years ago

How do water and gravity work together to erode soil, sediment, and rock?

TiliK225 [7]

Gravity can cause water to move down and carry sediment and rocks along the bottom. if the water slows down, it drops the rocks and if it floods a field then the grass will also filter smaller particles out leaving fine sediment behind. In addition to it the fast flow of water can cause erosion, over time it can cause valleys as well.

7 0

3 years ago

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges $\rm q_1$ and $\rm q_2$ which are separated by the distance $\rm d$ is given by

$\rm F = \dfrac{kq_1q_2}{d^2}.$

<em>where,</em> k is the Coulomb's constant.

For the case, when,

$\rm q_1 = Q.$
$\rm q_2 = Q.$
$\rm d=r.$
$\rm F=12.3442.$

Then, using Coulomb's law,

$\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).$

For the case, when,

$\rm q_1 = 2Q.$
$\rm q_2 = 2Q.$
$\rm d=\dfrac r2.$

Then, using Coulomb's law, the new electric force between the charges is given by,

$\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.$

8 0

2 years ago

A weight lifter struggles but manages to keep a heavy barbell abovehis head. Occasionally he slips and the barbell starts to fal

shutvik [7]

A) The lifter's and the barbell's force are equal and opposite in direction
B) The lifter's force is greater than that of the barbell and in the upward direction
C) The barbell's force is greater than that of the lifter and in the downward direction

4 0

2 years ago

Read 2 more answers