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kondor19780726 [428]
3 years ago
7

Explain how the emissions trading program works and identify one major advantage and one major disadvantage WILL GIVE BRAINLIEST

PLZ ANSWER ASAP
Chemistry
1 answer:
Liula [17]3 years ago
3 0

Answer:

Explanation:

The emissions trading program work to set an environmental goal to control pollution. The program is working to reduce the overall pollution effect by

<em>Install pollution control technology, such as a scrubber to remove pollution before it comes out of the smokestack. </em>

<em>Replace existing pollution controls with more advanced technologies. </em>

<em>Tune-up existing controls so they run better. </em>

<em>Switch to alternative fuels that emit less pollution. </em>

<em>Shift production to lower emitting or more efficient units.</em>

<em />

<em />

You might be interested in
Calculate the empirical formula for each natural flavor based on its elemental mass percent composition.
algol [13]
The complete question is;
Calculate the empirical formula for each of the following naturalflavors based on their elemental mass percent composition.

Q1)
methyl butyrate (component of apple taste andsmell):  C -58.80 %  H- 9.87 % 
O -31.33.%Express your answer as a chemical formula.


Q2)
vanillin (responsible for the taste and smellof vanilla):  C - 63.15%  H- 5.30 % 
O - 31.55%Express your answer as a chemical formula.

Q1)
empirical formula is the simplest ratio of whole number of elements in the compound. as the percentages have been given, lets calculate for 100 g of compound 
                                          C                         H                         O
mass                             58.80 g                  9.87 g                   31.33
molar mass                   12 g/mol                 1 g/mol                 16 g/mol
number of moles           58.80/12                9.87/1                    31.33/16
                                      = 4.9                      =9.87                     = 1.95
then divide number of moles by least number of moles - 1.95 in this case
                                      4.9/1.95 = 2.51      9.87/1.95 = 5.06    1.95/1.95= 1
next multiply by 2 to get numbers that can be rounded off to whole numbers
                                       2.51x2 = 5.02        5.06x2 = 10.12      1x2 = 2
when rounded off to the nearest whole number 
C - 5
 H - 10
 O - 2
therefore empirical formula is C₅H₁₀O₂

Q2) for this too since elemental composition has been given in percentages lets calculate for 100 g of compound 
                                          C                         H                         O
mass                               63.15 g                5.30 g                 31.55 g
molar mass                     12 g/mol              1 g/mol                16 g/mol
number of moles             63.15/12             5.30/1                  31.55/16
                                        =5.26                  =5.30                   =1.97
divide the number of moles by the least number of moles - 1.97
                                        5.26/1.97            5.30/1.97               1.97/1.97 
                                        =2.67                   = 2.69                      = 1
multiply each by 3 to get numbers that can be rounded off to whole numbers
                                        2.67x3 = 8.01     2.69x3 = 8.07         1x3 = 3
rounded off to the nearest whole numbers 
C - 8
H - 8
O - 3
empirical formula = C₈H₈O₃
7 0
3 years ago
You burn a 1.5 g jellybean to warm 150 g of water. The temperature of the water increases by 15 °C. Water has a specific heat of
Schach [20]

Answer:

9414.0 J.

Explanation:

  • The amount of heat absorbed by water through burning a 1.5 g jellybean can be calculated from the relation:

<em>Q = m.c.ΔT.</em>

where, Q is the amount of heat absorbed by water,

m is the mass of water (m = 150.0 g),

c is the specific heat of water (c = 4.184 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 15.0 °C).

<em>∴ Q = m.c.ΔT</em> = (150.0 g)(4.184 J/g °C)(15.0 °C) = <em>9414.0 J. </em>

  • <em>So, the jellybean have 9414.0 J that is releases to water.</em>
3 0
4 years ago
Explain How the concentration of hydronium ions and hydroxide ions are related ti ph.
sladkih [1.3K]
PH becomes lower when the H+ ion concentration increases. 
<span>pH becomes higher when the H+ ion concentration decreases. </span>

<span>pH becomes lower when the OH- ion concentration decreases. </span>
pH becomes higher when the OH- ion concentration increases.

Hope this helps!
7 0
3 years ago
A cylinder of lead has a radius of 4.0cm and a height of 10.0cm. What is the mass of the cylinder of lead?
Korolek [52]

Answer:

Explanation:

So lead has a density of 11.34 g/cm^3 according to a quick google search.  If this is not the value you are using, just replace what you do use where I put 11.34

knowing the density, if we knew the volume we could find the mass by unit conversion since g/cm^3 * cm^3 = g, so we would multiply the density by the volume.  And the question gives us the means to find the volume.

Volume of a cylinder is area of its base times the height.  Area of its base, a circle (since it's a cylinder) is π*r^2 where r is the radius and π is roughly 3.14.  I will leave π as the symbol until the end so it's easier to deal with.

So volume = area * height = πr^2*h = π4^2*10 = 160π (I moved pi to the back).  It's units are cm^3 since both measurements were in cm.  You can feel free to multiply π by 160 now if you like.  Anyway, now that we have the volume we multiply it by the density.  so 160π cm^3 * 11.34 g/cm^3 = 1814.4π g.  If you multiply that by 3.14 for π you get 5697.216 g.  And there's the mass.  Let em know if there was something you didn't understand.  

4 0
3 years ago
When methane reacts with oxygen, the products are carbon dioxide (CO2) and water (H2O). How many grams of water are formed if 24
VashaNatasha [74]

Answer:

54 g

Explanation:

To solve this problem we will simply follow the Law of conservation of mass.

According to this law:

" The mass of product in the chemical reaction must be equal to the mass of reactant"

Given data:

mass of methane= 24 g

mass of oxygen= 96 g

mass of carbon dioxide= 66 g

mass of water= ?

Solution:

CH4 + 2O2 → CO2 +2H2O

24g + 96 g = 66 g + ?

120 g = 66 g + ?

120 g - 66 g = 54 g

so 54 g of waters are produce.

We can see that mass of water is equal to the sum of masses of reactant minus mass of product formed i.e mass of carbon dioxide.

4 0
4 years ago
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