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vodka [1.7K]
3 years ago
6

The image shows a representative sample of 50 atoms of a fictious element, called lemonium ( Le ). Lemonium consists of three is

otopes. The red spheres are Le – 19 , the light blue spheres are Le – 17 , and the dark blue spheres are Le – 15 . Determine the percent natural abundance of each of the three isotopes.
Chemistry
1 answer:
Keith_Richards [23]3 years ago
3 0

The percentage abundance is a measure of ratio of the number of each isotope and the total number of the element. The percentage abundance of each isotope is :

  • Le - 19 = 0.32
  • Le - 17 = 0.44
  • Le - 15 = 0.24

Number of each isotope in the sample :

  • Le - 19 = 16
  • Le - 17 = 22
  • Le - 15 = 12

Total number of sample = 50

The percentage natural abundance of the isotopes can be calculated :

Number of each isotope ÷ total number of sample

Percentage abundance of Le isotopes

  • Le - 19 = \frac{16}{50}=0.32
  • Le - 17 = \frac{22}{50}=0.44
  • Le - 15 = \frac{12}{50}=0.24

Therefore, the percentage abundance of Le - 19, Le - 17 and Le - 15 isotopes are 0.32, 0.44 and 0.24 respectively.

Learn more : brainly.com/question/16078327

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Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
posledela

The new volume : 21.85 ml

<h3>Further explanation</h3>

Given

V1=25,0 ml

P1=725 mmHg

T1=298K is converted to

T2=273'K

P2=760 mmHg atm

Required

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Solution

Combined gas law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

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5 0
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7 0
2 years ago
Complete combustion of 2.60 g of a hydrocarbon produced 8.46 g of co2 and 2.60 g of h2o. what is the empirical formula for the h
zubka84 [21]
1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon. 
Hence, in this case the mass of carbon in 8.46 g of CO2:
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Therefore, with the amount of carbon and hydrogen from the hydrocarbon we can calculate the empirical formula.
We first calculate the number of moles of each,
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Hydrogen = 0.2889/1 = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing with the smallest number value;
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  0.1923/0.1923 : 0.2889/0.1923
                       1 :  1.5
                      (1 : 1.5) 2
                     = 2 : 3
Hence, the empirical formula of the hydrocarbon is C2H3
5 0
3 years ago
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