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maks197457 [2]
3 years ago
14

108J of work was done on a closed sysem. During this phase of the experiment, 79J of heat was added to the system.What was the t

otal change in the internal energy of the system.
Physics
1 answer:
skelet666 [1.2K]3 years ago
7 0

The change in internal energy of the system is +187 J

Explanation:

According to the first law of thermodynamics, the change in internal energy of a system is given by the equation:

\Delta U = Q + W

where

\Delta U is the change in internal energy

Q is the heat absorbed by the system

W is the work done on the system

For the system in this problem, we have

W = +108 J is the work done on it

Q = +79 J is the hear added to it

So, the change in internal energy is

\Delta U = 108 + 79 = +187 J

Learn more about thermodynamics here:

brainly.com/question/4759369

brainly.com/question/3063912

brainly.com/question/3564634

#LearnwithBrainly

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