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ryzh [129]
3 years ago
10

What is a molecule made of?provide an example of one .

Chemistry
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

a molecule is made of two or more atoms bonded together. h2o would be a molecule

Explanation:

You might be interested in
Which of the following words means "the degree to which a measurement is precise and reliable"?
Vikki [24]
B, because that’s the simplified definition of accuracy
7 0
3 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
3 years ago
Chlorine has two natural isotopes: Cl-37 and Cl-35. Hydrogen reacts with chlorine to form the compound HCl. Would a given amount
jolli1 [7]

Answer: Yes, a given amount of Hydrogen would react with different masses of the two isotopes of chlorine, and no, this does <em>not</em> conflict with the Law of Definite proportions

Explanation:

About 76% percent of Cl is found in the Cl-35 isotope, and about  24% in the Cl.37 isotope. that means that about 24% of Cl nuclei have 2 more neutrons than the average Cl nucleus.

So, if H_2 reacts with Cl_2, 76% of the Hydrogen that reacted will react with Cl-35, and the rest will react with Cl-37. Why does this not conflict with the law of definite proportions? Because each Hydrogen atom ends up paired to a single Chlorine atom! Moreover, the proportion of Cl-35 to Cl-37 remains constant in all samples of Chlorine that are naturally found, thus we will always find the same proportion of Chlorine to Hydrogen in any HCl sample we come across.  Thus the weight of a mol of Cl will always be 35*0.76+37*0.24=35.48 or 35.45 if we had done this calculation with more significant digits.

Therefore 1 mol of H_2 (2 grams) will always react with 1 mol of Cl_2 (35.45g*2=70.9 grams), and this is a definite proportion.

5 0
4 years ago
What is the total number of valence electrons in a carbon atom in the ground state
kolbaska11 [484]
Carbon will have 4 valence electrons.  It will have 2 in the p orbital and 2 in the s orbital.  You can see this when you find the noble gas configuration of carbon which is [He]2s²2p² showing that carbon has 4 valence electrons.
I hope this helps.  Let me know if anything is unclear.
6 0
3 years ago
Two hundred kg of liquid contains 30% butane, 40% pentane, and the rest hexane (mass %) Determine: The mole fraction composition
OlgaM077 [116]

Answer:

The mole fraction composition of the liquid is :

Mole fraction of butane, pentane and hexane are 0.3638,0.3908 and 0.2454 respectively.

Explanation:

Mass of the liquid mixture = 200 g

Percentage of butane = 30%

Mass of butane = \frac{30}{100}\times 200 g=60 g

Moles of butane = n_1=\frac{60 g}{58 g/mol}=1.0345 mol

Percentage of pentane= 40%

Mass of pentane= \frac{40}{100}\times 200 g=80 g

Moles of pentane= n_2=\frac{80 g}{58 g/mol}=1.1111 mol

Percentage of hexane = 100% - 30% - 40% = 30%

Mass of hexane = \frac{30}{100}\times 200 g=60 g

Moles of hexane = n_2=\frac{60 g}{86 g/mol}=0.6977 mol

Mole fraction of butane, pentane and hexane : \chi_1, \chi_2 \& \chi_3

\chi_1=\frac{n_1}{n_1+n_2+n_3}=\frac{1.0345 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.3638

\chi_2=\frac{n_2}{n_1+n_2+n_3}=\frac{1.1111 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.3908

\chi_3=\frac{n_1}{n_1+n_2+n_3}=\frac{0.6977 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.2454

4 0
4 years ago
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