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maw [93]
3 years ago
8

What are reasons standardizing conditions in which chemist describe matter?

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
7 0
Matter is the basic unit of every thing in the world, whether living or nonliving. So, it is logical to set definitions and postulates because these could pave way to other complexities of science. It is the foundation of science. That is why theories and laws are formulated for matter such as: Kinetic Theory of Matter, Dalton's Atomic Model, Newton's Law of Motion, Conservation Laws and many more.
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Write the step by step process of digestion in ruminants using 4 square method.
Vaselesa [24]

The digestion process in Ruminants begins by chewing and swallowing their food.

<h3>What are ruminants?</h3>

A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

brainly.com/question/26752412

#SPJ1

3 0
2 years ago
Identify the Following as either Alkanes, alkynes or alkenes
puteri [66]

Answer:

The answer to your question is below

Explanation:

To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.

Alkanes           Cn H(2n + 2)

Alkenes           Cn H (2n)              "n" is the number of Carbons

Alkynes            Cn H (2n - 2)

a) CH₄             C₁ H 2(1) +2   = C₁H₂ + ₂ = CH₄       Alkane

b) C₂H₄            C₂ H₂(₂)                                           Alkene

c) C₃H₆             C(₃) H₂ (₃)                                        Alkene

d) C₂H₂            C₂ H₂(₂) - 2  = C₂H₄ - ₂ = C₂H₂        Alkyne

e) C₁₀H₂₂          C₁₀ H₂(₁₁)                                          Alkene

5 0
3 years ago
Read 2 more answers
The electrolysis of water forms H2 and O2. 2H2O 2H2 + O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the de
BigorU [14]

<u>Answer:</u> The percent yield of oxygen gas is 67.53 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of water = 17.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{17.0g}{18g/mol}=0.944mol

For the given chemical equation:

2H_2O\rightarrow 2H_2+O_2

By Stoichiometry of the reaction:

2 moles of water produces 1 mole of oxygen gas

So, 0.944 moles of water will produce = \frac{1}{2}\times 0.944=0.472moles of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = 0.472 moles

Putting values in equation 1, we get:

0.472mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.472mol\times 32g/mol)=15.104g

To calculate the percentage yield of oxygen gas, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of oxygen gas = 10.2 g

Theoretical yield of oxygen gas = 15.104 g

Putting values in above equation, we get:

\%\text{ yield of oxygen gas}=\frac{10.2g}{15.104g}\times 100\\\\\% \text{yield of oxygen gas}=67.53\%

Hence, the percent yield of oxygen gas is 67.53 %.

7 0
4 years ago
Read 2 more answers
Which among the following pairs are not isotopes?​
topjm [15]
Hydrogen and Deuterium
8 0
4 years ago
Write correctly a balanced equation for the following "word" equation: Red lead → lead monoxide + oxygen​
Nat2105 [25]

Answer:

nothing haha because I don't know what is the answer

6 0
2 years ago
Read 2 more answers
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