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andriy [413]
3 years ago
15

Two blocks, m1=70.0kg and m2=120.0kg, are connected as shown. The coefficient of friction between surfaces in contact is 0.250.

a. Which way will the system move? b. What is the acceleration of the blocks?
Physics
1 answer:
andriy [413]3 years ago
3 0
If they are connected exactly as shown, nothing can happen.
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A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

F_1 + F_2 = 15009.3 N

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

F_1(1.15) = F_2(2.70 - 1.15)

F_1 = 1.35 F_2

now from above equation

F_2 + 1.35F_2 = 15009.3

now we have

F_2 = 6392.85 N

now the other force is given as

F_1 = 8616.45 N

4 0
4 years ago
Plz do all plz i will give brainest and thanks to best answer do it right
lara31 [8.8K]

Answer:

I'm not really sure but I think it's choice a

5 0
3 years ago
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A body travels at an initial speed of 2.5 m/s. Given a constant acceleration of 0.2 m/s 2 what is the speed of the body at time
garri49 [273]

Answer:

<u>We are given:</u>

u = 2.5 m/s

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t = 25 seconds

v = v m/s

<u>Solving for 'v':</u>

From the first equation of motion:

v = u + at

Replacing the values

v = 2.5 + (0.2)(25)

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6 0
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To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

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Here,

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\theta = Angle when occurs the interference point of destructive interference

Our values are given as,

\text{Wavelength} = \lambda = 400nm = 4*10^{-7}m

\text{Distance of Screen} = D = 1m

Using the previous expression we have,

d \times \theta = \frac{\lambda}{2}

d \times (0.1) = \frac{4*10^{-7}}{2}

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Mazyrski [523]

Answer:

heat and power

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