Answer:
The speed at the bottom of the driveway is3.67m/s.
Explanation:
Height,h= 5sin20°= 1.71m
Potential energy PE=mgh= 2000×9.8×1.71
PE= 33516J
KE= PE- Fk ×d
0.5mv^2= 33516 - (4000×5)
0.5×2000v^2= 33516 - 20000
1000v^2= 13516
v^2= 13516/1000
v =sqrt 13.516
v =3.67m/s
Answer:
speed of golf ball is 1.15 ×
m/s
and % of uncertainty in speed = 2.07 ×
%
Explanation:
given data
mass = 45.9 gram = 0.0459 kg
speed = 200 km/hr = 55.5 m/s
uncertainty position Δx = 1 mm =
m
to find out
speed of the golf ball and % of speed of the golf ball
solution
we will apply here heisenberg uncertainty principle that is
uncertainty position ×uncertainty momentum ≥
......1
Δx × ΔPx ≥
here uncertainty momentum ΔPx = mΔVx
and uncertainty velocity = ΔVx
and h = 6.626 ×
Js
so put here all these value in equation 1
× 0.0459 × ΔVx = 
ΔVx = 1.15 ×
m/s
and
so % of uncertainty in speed = ΔV / m
% of uncertainty in speed = 1.15 ×
/ 55.5
% of uncertainty in speed = 2.07 ×
%
Answer:
a force is represented by a<u> vector </u>the choice of a <u>reference frame</u> is necessary
Explanation:
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
Answer:
hope this answer helps this is what I understand