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2 years ago

How does water in a hot spring get hot?

Physics

1 answer:

OLEGan [10]2 years ago

4 0

Water may come into contact with very hot rock heated by magma

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When the Moon is directly between the Sun and Earth, a _____ tide will occur along a shoreline that is facing the Moon.

Temka [501]

<span>When the Moon is directly between the Sun and Earth, a spring tide will occur along a shoreline that is facing the Moon. </span>

8 0

3 years ago

4. A car accelerating at 60 meters/second is hit in an accident by a bus. The net force exerted on

Licemer1 [7]

Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

3 0

2 years ago

A hot-water stream at 80 ℃ enters a mixing chamber with a mass flow rate of 0.5 kg/s where it is mixed with a stream of cold wat

rewona [7]

Answer:

$\dot{m_{2}}=0.865 kg/s$

Explanation:

$\dot{m_1}= 0.5kg/s$

from steam tables , at 250 kPa, and at

T₁ = 80⁰C ⇒ h₁ = 335.02 kJ/kg

T₂ = 20⁰C⇒ h₂ = 83.915 kJ/kg

T₃ = 42⁰C ⇒ h₃ = 175.90 kJ/kg

we know

$\dot{m_{in}}=\dot{m_{out}}$

$\dot{m_{1}}+\dot{m_{2}}=\dot{m_{3}}$

according to energy balance equation

$\dot{m_{in}}h_{in}=\dot{m_{out}}h_{out}$

$\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=\dot{m_{3}}h_{3}$

$\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=(\dot{m_{1}}+\dot{m_{2}})h_{3}\\(0.5\times 335.02)+(\dot{m_{2}}\times 83.915)=(0.5+\dot{m_{2}})175.90\\\dot{m_{2}}=0.865 kg/s$

4 0

3 years ago

A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exe

Karolina [17]

Answer:

The velocity is 40 ft/sec.

Explanation:

Given that,

Force = 3200 lb

Angle = 30°

Speed = 64 ft/s

The resistive force with magnitude proportional to the square of the speed,

$F_{r}=kv^2$

Where, k = 1 lb s²/ft²

We need to calculate the velocity

Using balance equation

$F\sin\theta-F_{r}=m\dfrac{d^2v}{dt^2}$

Put the value into the formula

$3200\sin 30-kv^2=m\dfrac{d^2v}{dt^2}$

Put the value of k

$3200\times\dfrac{1}{2}-v^2=m\dfrac{d^2v}{dt^2}$

$1600-v^2=m\dfrac{d^2v}{dt^2}$

At terminal velocity $\dfrac{d^2v}{dt^2}=0$

So, $1600-v^2=0$

$v=\sqrt{1600}$

$v=40\ ft/sec$

Hence, The velocity is 40 ft/sec.

4 0

3 years ago

The total negative charge on the electrons in 1mol of helium (atomic number 2, molar mass 4) is ________?

DaniilM [7]

Answer:

$1.92\times 10^5 C$

Explanation:

We are given that

Atomic number=2

We have to find the total negative charge on the electrons in one mole of Helium.

We know that atomic number=Proton number

Proton number=Number of electrons=2

Number of electrons in Helium=2

1 mole of Helium= $6.02\times 10^{23}$ atoms

We know that q=ne

Where n =Number of fundamental units

e=Charge on electron

1 e= $1.6\times 10^{-19}C$

Using the formula

$q=2\times 1.6\times 10^{-19}=3.2\times 10^{-19}C$

Total negative charge in 1 mole= $3.2\times 10^{-19}\times 6.02\times 10^{23}=1.92\times 10^5C$

Hence, the total negative charge on the electrons in 1 mole of Helium= $1.92\times 10^5 C$

4 0

3 years ago