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romanna [79]
3 years ago
13

A woman stands on a scale in a moving elevator. Her massis

Physics
1 answer:
Luden [163]3 years ago
8 0

Answer:

Explanation:

Combined mass = 815 + 60 = 875 kg

Net weight acting downwards

= 875 x 9.8

= 8575 N

Tension in the string acting upwards

= 9410

Net upward force = 9410 - 8575

= 835 N

Acceleration

Force / mass

a = 835 / 875

a = .954 ms⁻²

Since the elevator is going up with acceleration a

Total reaction force on the woman from the ground

= m ( g + a )

60 ( 9.8 + .954)

= 645.25 N.

Reading of scale = 645.25 N

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Answer:

4n

Explanation:

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The winch takes in cable at the constant rate of 130 mm/s. if the cylinder mass is 115 kg, determine the tension in cable 1. neg
nikitadnepr [17]
By applying Newton's second law of motion;

ma = mg - T

Where,
m = mass; a = downward accelerations (+ve value) or upward acceleration (-ve value); g = gravitational acceleration; T = tension.

For the current case, the velocity is constant therefore,
a = 0

Then,
0 = mg - T
T = mg = 115*9.81 = 1128.15 N

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4 years ago
A theory is a framework of ideas and assumptions used to explain some set of observations and to make predictions about the real
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All the predictions in the impact theory are true.

Explanation:

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What makes a force a vector quantity
klasskru [66]

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A vector quantity is a quantity that has both magnitude and direction.

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3 years ago
A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the ma
Zielflug [23.3K]

The maximum height reached by the ball is 0.46m.

To find the answer, we have to know about the potential energy of a spring mass system.

<h3>How to find the maximum height reached by the ball?</h3>
  • It is given that,

                       k=400N/m\\m=1kg\\x=0.150m\\h=?\\

  • We have to find the maximum height reached by the ball.
  • Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,

                             U=\frac{1}{2}kx^2 \\U=mgh

  • Combining both, we get,

                    h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m

Thus, we can conclude that, the maximum height reached by the ball is 0.46m.

Learn more about the potential energy here:

brainly.com/question/26962934

#SPJ4

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1 year ago
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