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3 years ago

On a production possibilities curve, any point that falls outside the frontier line is considered

Physics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

The Production Possibilities Curve (PPC) is a model used to show the tradeoffs associated with allocating resources between the production of two goods. The PPC can be used to illustrate the concepts of scarcity, opportunity cost, efficiency, inefficiency, economic growth, and contractions.

Explanation:

I hope this helps

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Answer these questions please and you will get the brain list

Naddika [18.5K]

I am using the equation F=ma (force equals mass times acceleration) to solve these problems.

1. You are looking for force, and have mass and acceleration. You just plug in the values for mass and acceleration to get the force needed.

F=(15kg)(5m/s^2)

F=75N

2. Again, you are looking for force, and just need to plug in the values for mass and acceleration

F=(3kg)(2.4m/s^2)

F=7.2N

3. In this problem, you have force and mass, but need to find acceleration. To do this, you need to get acceleration alone on one side of the equation - divide each side by m. Your equation will now be F/m=a

a=(5N)/(3.7kg)

a=18.5m/s^2

I did not use significant figures. Let me know if you need to do that and need any help on that. Hope this helps!

7 0

3 years ago

What is the full form of work?

Pepsi [2]

Answer: JOB

Explanation: They full forms of work are JOB which is JUST OBEY BOSS or Joining Other Bussiness .

7 0

3 years ago

In which of these cases do we have enough information to say that the atom is electrically neutral?

Luba_88 [7]

<span>So we want to know when do we have enough information about the atom that we can say that it is electrically neutral. So the information we need to know is the number of protons, whic are positively charged particles and the number of electrons which are negatively charged particles. Number of protons has to be equal to number of electrons for the atom to have neutral charge. Neutrons are electrically neutral so their number doesn't change the charge of the atom. So the correct answer is B. </span>

5 0

3 years ago

Read 2 more answers

A factory worker pushes a 32.0 kgkg crate a distance of 4.0 mm along a level floor at constant velocity by pushing horizontally

Luda [366]

Answer:

a) The force that the worker must apply has a magnitude of 75.317 newtons.

b) The external force does a work of 0.301 joules.

c) The friction force does a work of -0.301 joules.

d) Both normal force and gravity have done a work of 0 joules.

e) The total work done on the crate is 0 joules.

Explanation:

a) As the crate is moving at constant velocity, we know that magnitude of the force done on the crate must be equal to the friction force. Hence, we must use the following formula:

$F = \mu\cdot m\cdot g$ (1)

Where:

$F$ - External force, in newtons.

$\mu$ - Coefficient of kinetic friction, no unit.

$m$ - Mass, in kilograms.

$g$ - Gravity acceleration, in meters per square second.

If we know that $\mu = 0.24$ , $m= 32\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the external force is:

$F = (0.24)\cdot (32\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F = 75.317\,N$

The force that the worker must apply has a magnitude of 75.317 newtons.

b) The direction of the force is parallel to the direction of motion. The work done by this force ( $W_{F}$ ), in joules, is determined by this formula:

$W_{F} = F\cdot \Delta s$ (2)

Where $\Delta s$ is the distance travelled by the crate, in meters.

If we know that $F = 75.317\,N$ and $\Delta s = 0.004\,m$ , then the work done by the force is:

$W_{F} = (75.317\,N)\cdot (0.004\,m)$

$W_{F} = 0.301\,J$

The external force does a work of 0.301 joules.

c) The direction of the friction force is antiparallel to the direction of motion. The work done by this force ( $W_{f}$ ), in joules, is determined by this formula:

$W_{f} = -W_{F}$ (3)

$W_{f} = -0.301\,J$

The friction force does a work of -0.301 joules.

d) The direction of the normal force is perpendicular to the direction of motion. Therefore, no work is done due to normal force.

$W_{N} = 0\,J$

Likewise, no work is done by gravity.

$W_{g} = 0\,J$

Both normal force and gravity have done a work of 0 joules.

e) The total work is the sum of the works done by the external force and the friction force:

$W = W_{F}+W_{f}$

$W = 0.301\,J - 0.301\,J$

$W = 0\,J$

The total work done on the crate is 0 joules.

5 0

2 years ago

How many kilojoules is this?

Margaret [11]

Answer:

How to convert joules to kilojoules

One joule is equal to thousandth of a kilojoule:

1J = 0.001kJ

The energy in kilojoules E(kJ) is equal to the energy in joules E(J) divided by 1000:

E(kJ) = E(J) / 1000

Example

Convert 500 joules to kilojoules.

The energy E in kilojoules (kJ) is equal to 500 joules (J) divided by 1000:

E(kJ) = 500J / 1000 = 0.5kJ

Joules to kilojoules conversion table

Energy (J) Energy (kJ)

1 J 0.001 kJ

2 J 0.002 kJ

3 J 0.003 kJ

4 J 0.004 kJ

5 J 0.005 kJ

6 J 0.006 kJ

7 J 0.007 kJ

8 J 0.008 kJ

9 J 0.009 kJ

10 J 0.01 kJ

20 J 0.02 kJ

30 J 0.03 kJ

40 J 0.04 kJ

50 J 0.05 kJ

60 J 0.06 kJ

70 J 0.07 kJ

80 J 0.08 kJ

90 J 0.09 kJ

100 J 0.1 kJ

200 J 0.2 kJ

300 J 0.3 kJ

400 J 0.4 kJ

500 J 0.5 kJ

600 J 0.6 kJ

700 J 0.7 kJ

800 J 0.8 kJ

900 J 0.9 kJ

1000 J 1 kJ

2000 J 2 kJ

3000 J 3 kJ

4000 J 4 kJ

5000 J 5 kJ

6000 J 6 kJ

7000 J 7 kJ

8000 J 8 kJ

9000 J 9 kJ

10000 J 10 kJ

100000 J 100 kJ

hope it help u

itz by Riddhi

4 0

3 years ago