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OlgaM077 [116]
3 years ago
5

A theory is a framework of ideas and assumptions used to explain some set of observations and to make predictions about the real

world. Each of the three theories for the formation of the Moon lead to different predictions about evidence that we should find. Which of the following predictions should be true if each theory is correct? The theories of the Moon's formation make different predictions:
Coformation theory:

•The Moon and Earth should have very similar compositions.
•The Moon and Earth should have similar densities.

Capture theory:

•The Moon and Earth should have completely different compositions.
•Mathematical models should predict that the capture of a Moon-sized satellite would be likely in Earth's early history.

Impact theory:

•Earth and the Moon should have similar mantles and dissimilar cores.
•Computer simulations should predict that a collision between Earth and a Mars-sized object would produce a Moon-sized satellite with a stable orbit.

If any of the theories are true, their predictions should bear out in the actual evidence.
Physics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:

All the predictions in the impact theory are true.

Explanation:

That’s because of their predictions. Modern computer simulations predict that there happened a collision between Earth and a planet named as Theia. The chunks of both planets conformed into a stable orbit and form the satellite that we know today as our Moon. Similarly, both moon and Earth share similar mantle compositions but cores are dissimilar in terms of their size and composition.

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Solution

distance travelled by Chris

\Delta t=\frac{1}{3600}hr.

X_{c}= [(\frac{21+0}{2})+(\frac{33+21}{2})+(\frac{55+47}{2})+(\frac{63+55}{2})+(\frac{70+63}{2})+(\frac{76+70}{2})+(\frac{82+76}{2})+(\frac{87+82}{2})+(\frac{91+87}{2})]\times\frac{1}{3600}

=\frac{579.5}{3600}=0.161miles

Kelly,

\Delta t=\frac{1}{3600}hr.

X_{k}=[(\frac{24+0}{2})+(\frac{3+24}{2})+(\frac{55+39}{2})+(\frac{62+55}{2})+(\frac{71+62}{2})+(\frac{79+71}{2})+(\frac{85+79}{2})+(\frac{85+92}{2})+(\frac{99+92}{2})+(\frac{103+99}{2})]\times\frac{1}{3600}

=\frac{657.5}{3600}

\Delta X=X_{k}-X_{C}=0.021miles

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