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3 years ago

Find the pH of a solution whose H concentration is 0.7 x 10-3.

Chemistry

1 answer:

dexar [7]3 years ago

6 0

Answer: pH = 3.15

Explanation: Solved in the attached picture.

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Mariana [72]

Answer:

Explanation:

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4 0

3 years ago

What is the molar mass of water in the hydrate? FeSO4 • 7H2O

Rainbow [258]

M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol

5 0

4 years ago

When heated a sample consisting of only CaCO3 and MgCO3 yields a mixture of CaO and Mgo. If the weight of the combined oxides is

ExtremeBDS [4]

Answer:

38.83 % of CaCO3

61.17 % of MgCO3

Explanation:

where Moles of CaCO3 is equals to x and MgCO3 is y we have that...

CaCO3 molar mass = 100.09 g / mol = 100.09 x

MgCO3 molar mass = 84.31 g / mol = 84.31 y

decomposition reactions :

CaCO3 ---> CaO + CO2

MgCO3 ---> MgO + CO2

So we have that , Moles of CaO = Moles of CaCO3 = x

and Moles of MgO = Moles of MgCO3 = y

CaO molar mass = 56.08 g / mol

MgO molar mass = 40.30 g / mol

CaO = 56.08 x

MgO = 40.30 y

"If the weight of the combined oxides is equal to 51.00% of the initial sample weight,"

total mass of MgO and CaO = 51.00 % of Total Mass of MgCO3 and CaCO3

thus

56.08 x + 40.30 y = 0.51 ( 100.09 x + 84.31 y )

56.08 x + 40.30 y = 51.04 x + 42.99y

5.04 x = 2.7 y

y = 1.87 x

CaCO3 % in the sample

= 100.09 x × 100 / ( 100.09 x + 84.31 y )

= 10009 x / ( 100.09 x + 84.31 × 1.87 x )

= 10009 x / ( x ( 100.09 + 157.66 ) )

= 10009 / 257.75

= 38.83 %

MgCO3 % in the sample

= 100 - 38.83

= 61.17 %

7 0

3 years ago

How many moles of silver chloride are produced from 15.0 moles of silver nitrate

Ghella [55]

15.0 moles of silver chloride are produced.

7 0

3 years ago

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

2SO2 + O2 ⇄ 2SO3

Initial 3.4 atm 1.3 atm 0 atm

Change -2x - x + 2x

Equilibrium 3.4 - 2x 1.3 -x 0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

2SO2 + O2 ⇄ 2SO3

Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm

Equilibrium 2.88 atm 1.04 atm 0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

$Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135$

8 0

3 years ago