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Triss [41]
4 years ago
5

Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the

amount of impulse given to the wall? Be sure to show all work to support your answer.
Physics
1 answer:
bulgar [2K]4 years ago
6 0
So we are told that the ball rebounds elastically. What this means momentum and kinetic energy is conserved. So our initial condition equals our final condition.

Our initial condition is when the ball is moving at 8m/s and is 15 kg.

p_0 = (8m/s)(15kg) = 120kg*m/s

Next we our told it bounces off in the negative direction moving at 8m/s

p_f = (-8m/s)(15kg) = -120kg*m/s

Impulse, denoted as J, which is the change in momentum.

J=p_f-p_0 = -120kg*m/s - 120kg*m/s = -240kg*m/s

J = -240kg*m/s

Hope this helps! :D
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4 years ago
A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci
Simora [160]

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

4 0
3 years ago
What is equilibrium????
IrinaK [193]

Answer:

Explanation:

An equilibrium is a state in which opposing forces or influences are banned.

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3 years ago
Read 2 more answers
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