The final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
<h3>
Conservation of linear momentum</h3>
The final velocity of the other student will be determined by applying the principle of conservation of linear momentum for elastic collision.
- let u represent initial velocity
- let v represent final velocity
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Substitute the given parameters and solve for final velocity of the other stsudent.
74(7.6) + 81(0) = 74(0) + 81(v₂)
562.4 = 81v₂
v₂ = 562.4/81
v₂ = 6.94 m/s
Thus, the final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
Magnetic field, B = 1.9232 T
Explanation:
Given data:
Value of the charge, Q = 0.026 C
Speed, V = 443.592 m/s
Force experienced, F = 22.182
Now,
the Force (F) experienced by a charge in a magnetic field is given as:
F = QVBsinθ
where,
B is the magnetic field
Angle between the magnetic field and the velocity.
since, the velocity is in horizontal direction and the magnetic field is downwards. Therefore, the angle θ = 90°
thus, we have
22.182 = 0.026 × 443.592 × B × sin90°
or
B = 1.9232 T
Answer:
Yes! im not sure if this is correct :)
Explanation:
Answer:
Explanation:
Assume that the bullet is shot at a velocity of (v m/s) and it will take t time to pass the second plate.
by the definition of then angular velocity (ω)
ω=\frac{angular displacement}{time }[/tex]
Lets find the time to turn the next plate by 12 degrees , using θ=ωt
]t=\frac{12}{8995.5} =1.334*10^{-3}[/tex]
the bullet has to travel 80cm in this much of time to make a hole in the second plate. We can find the speed using this equation
(we have to convert cm into meters first)