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Nostrana [21]
3 years ago
11

If we assume that the metallic plates are perfect conductors, the electric field in their interiors must vanish. given that the

electric field e⃗ due to a charged sheet with surface charge +σ is given by e=σ2ϵ0, and that it points away from the plane of the sheet, how can the condition that the electric field in plate i vanishes be written?
Physics
1 answer:
Svetlanka [38]3 years ago
7 0

here the charge density of metal plate is given as

charge density = \sigma

now the electric field is given Gauss law

\int E. dA = \frac{q}{\epsilon_0}

now here E = constant

so we will have

E. \int dA = \frac{q}{\epsilon_0}

Since total area on both sides of plate will be double and becomes 2A

E. 2A  = \frac{q}{\epsilon_0}

E = \frac{q/A}{2\epsilon_0}

E = \frac{\sigma}{2\epsilon_0}

Now if we will find the electric field inside the metal plate

Then as we know that total charge inside the plate will always be zero

so we have

E = 0

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bezimeni [28]

Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

2.2 x 10^-20

The answer is B.

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Firdavs [7]
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4 0
3 years ago
Light of wavelength 500nm is passed through a diffraction grating which has 400 lines per mm. What is the angular spectrum betwe
Citrus2011 [14]

Answer:

because of the gravity of the earth

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2 years ago
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Marat540 [252]
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3 years ago
A 2000 kg truck traveling north at 34 km/h turns east and accelerates to 58 km/h. (a) What is the change in the truck's kinetic
barxatty [35]

Explanation:

It is given that,

Mass of the truck, m = 2000 kg

Initial velocity of the truck, u = 34 km/h = 9.44 m/s

Final velocity of the truck, v = 58 km/h = 16.11 m/s

(a) Change in truck's kinetic energy, \Delta E=\dfrac{1}{2}m(v^2-u^2)

\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)

\Delta E=170418.5\ J

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