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Nostrana [21]
3 years ago
11

If we assume that the metallic plates are perfect conductors, the electric field in their interiors must vanish. given that the

electric field e⃗ due to a charged sheet with surface charge +σ is given by e=σ2ϵ0, and that it points away from the plane of the sheet, how can the condition that the electric field in plate i vanishes be written?
Physics
1 answer:
Svetlanka [38]3 years ago
7 0

here the charge density of metal plate is given as

charge density = \sigma

now the electric field is given Gauss law

\int E. dA = \frac{q}{\epsilon_0}

now here E = constant

so we will have

E. \int dA = \frac{q}{\epsilon_0}

Since total area on both sides of plate will be double and becomes 2A

E. 2A  = \frac{q}{\epsilon_0}

E = \frac{q/A}{2\epsilon_0}

E = \frac{\sigma}{2\epsilon_0}

Now if we will find the electric field inside the metal plate

Then as we know that total charge inside the plate will always be zero

so we have

E = 0

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