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liberstina [14]
3 years ago
8

According to Archimedes' principle, when an object is placed in a fluid, the buoyant force acting on it is equal to the weight o

f the fluid the object displaces. Question 3 options: True False
Physics
1 answer:
kolbaska11 [484]3 years ago
7 0
But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object. Thus, only in the special case of floating does the buoyant force acting on an object equal the object's weight
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A river has a steady speed 0.500 m/s. A student swims upstream a distance of1.00 km and swims back to the starting point. a) If
Ivahew [28]

Answer:

a) 33.6 min

b) 13.9 min

c)  Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).


Explanation:


The problem deals with relative velocities.

  • Call Vr the speed of the river, which is equal to 0.500 m/s
  • Call Vs the speed of the student in still water, which is equal to 1.20 m/s
  • You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
  • And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.

Now, you can state the equations for each section:

  • distance = speed × time
  • upstream: distance = (Vs - Vr) × t₁ = 1,000 m
  • downstream: distance = (Vs + Vr) × t₂ = 1,000 m

Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:

  • (Vs - Vr) × t₁ = 1,000 m
  • (1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
  • (1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
  • total time = t₁ + t₂ = 1429s + 588s =  2,017s
  • Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min

Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s


  • time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min

Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.

6 0
4 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
PolarNik [594]

OPTION C is the correct answer.

6 0
3 years ago
What are transverse waves and longitudinal waves have? how are they similar and different?
4vir4ik [10]
A transverse wave transfers energy perpendicular to the direction of wave motion. a longitudinal wave transfers energy parallel to the direction of the wave
3 0
3 years ago
Example of optical object​
Alik [6]

Answer:

Telescope,cameras

Hope it helped

5 0
3 years ago
Read 2 more answers
Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60
earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat,m_1=60 kg

Mass of another acrobat,m_2=50 kg

v_2=-3 m/s

v_1=5 m/s

We have to find their  velocity immediately after they grab  onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)V

Substitute the values

60\times 5+50(-3)=(60+50)V

300-150=110V

V=\frac{300-150}{110}=1.36m/s

4 0
3 years ago
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