All categories

2 years ago

The potential difference across the terminals of a battery is 8. 4v when there is a current of 1. 50 a in the ba

Physics

1 answer:

Vikentia [17]2 years ago

7 0

Answer:

The potential difference across the terminals of a battery is 8. 4v when there is a current of 1. 50 a in the ba

Explanation:

The potential difference across the terminals of a battery is `8.4 V` when there is a current of `1.50 A` in the battery from the negative to the positive terminal. When the current is `3.50 Air`, the reverse direction, the potential difference becomes `9.4 V`. (a) What is the internal resistance of the battery? (b) What is the emf of the battery?

You might be interested in

What is magnetic declination?

sdas [7]

I believe its B , (the direction the north end of a compass needle points, corresponding to the direction of the Earth's magnetic field lines)

5 0

3 years ago

Read 2 more answers

When were the following metals discovered:

Katen [24]

Answer:

A. 4000 BC

B. January 24, 1848

C. 1400 BC

Explanation:

Please mark brainliest.

3 0

3 years ago

Assume the acceleration of the object is a(t) = −9.8 meters per second per second. (Neglect air resistance.) A baseball is throw

wel

Answer:8.1 m

Explanation:

Given

ball is launched from height of 3 m

initial velocity $u=10 m/s$

considering the ball is thrown vertically upward

Using $v^2-u^2=2 as$

where,

u=initial velocity

v=final Velocity

a=acceleration

s=distance

At maximum height final velocity will be zero

$v^2-u^2=2 gs$

$0-10^2=2(-9.8)\cdot h$

$h=5.10 m$

Therefore maximum height w.r.t ground is $3+5.10=8.10 m$

8 0

2 years ago

Which physical phenomenon is illustrated by the fact that the prism has different refractive indices for different colors

alexandr402 [8]

Answer:

The incoming white light is composed of light of different colors,

Since these different colors have different refractive indices they are refracted at different angles from one another.

The output light is then separated by color creating a color spectrum.

Since n is greater for shorter wavelengths (violet colors) these wavelengths are refracted thru the larger angles.

5 0

3 years ago

An ideal Diesel cycle has a compression ratio of 18 and a cutoff ratio of 1.5. Determine the (1) maximum air temperature and (2)

weqwewe [10]

Answer:

(1) The maximum air temperature is 1383.002 K

(2) The rate of heat addition is 215.5 kW

Explanation:

T₁ = 17 + 273.15 = 290.15

$\frac{T_2}{T_1} =r_v^{k - 1} =18^{0.4} =3.17767$

T₂ = 290.15 × 3.17767 = 922.00139

$\frac{T_3}{T_2} =\frac{v_3}{v_2} = r_c = 1.5$

Therefore,

T₃ = T₂×1.5 = 922.00139 × 1.5 = 1383.002 K

The maximum air temperature = T₃ = 1383.002 K

(2)

$\frac{v_4}{v_3} =\frac{v_4}{v_2} \times \frac{v_2}{v_3} = \frac{v_1}{v_2} \times \frac{v_2}{v_3} = 18 \times \frac{1}{1.5} = 12$

$\frac{T_3}{T_4} =(\frac{v_4}{v_3} )^{k-1} = 12^{0.4} = 2.702$

Therefore;

$T_4 = \frac{1383.002}{2.702} =511.859 \ k$

$Q_1 = c_p(T_3-T_2)$

Q₁ = 1.005(1383.002 - 922.00139) = 463.306 kJ/jg

Heat rejected per kilogram is given by the following relation;

$c_v(T_4-T_1)$ = 0.718×(511.859 - 290.15) = 159.187 kJ/kg

The efficiency is given by the following relation;

$\eta = 1-\frac{\beta ^{k}-1}{\left (\beta -1 \right )r_{v}^{k-1}}$

Where:

β = Cut off ratio

Plugging in the values, we get;

$\eta = 1-\frac{1.5 ^{1.4}-1}{\left (1.5 -1 \right )18^{1.4-1}}= 0.5191$

Therefore;

$\eta = \frac{\sum Q}{Q_1}$

$\therefore 0.5191 = \frac{150}{Q_1}$

Heat supplied = $\frac{150}{0.5191} = 288.978 \ hp$

Therefore, heat supplied = 215491.064 W

Heat supplied ≈ 215.5 kW

The rate of heat addition = 215.5 kW.

7 0

3 years ago