Multiply these measurements, using significant digit rules:<br><br> 1.27 kg x 9.8 m/s2 = kg ∙ m/s2

A bicyclist starting from rest applies a force of F 195 N to ride his bicycle across flat ground for a distance of d- 290 m befo

laila [671]

Answer: a) 56,550 J b) 30.1 m/s c) 321 m

Explanation:

a) By definition, work, is the process that does an applied force, in order to produce a displacement in the same direction than the applied force, and can be written as follows;

W = F. d. (scalar product of two vectors)

In this case, as the force is parallel to the displacement, work is directly equal to the product of the applied force times the displacement (in magnitude), so we can write the following:

W = F. D = 195 N. 290 m = 56,550 J

b) In absence of friction, the work done by the force is equal to the change in the kinetic energy, as it can be showed using the work-energy theorem.

So, in this case, we can put the following:

W = ΔK ⇒F. D = 1/2 mv²

Solving for v, we get:

v=√2.F.D/m = 30.1 m/s

c) Now, if we assume that there is no friction between the bike and the ground, all the kinetic energy must become gravitational potential energy, at some height h.

We can write the following equation

m.g. h = 1/2 mv²

Simplifying, and taking g = 9.8 m/s², we can find h:

h= 46.2 m

Now, we need to know the distance travelled up the incline, which is related with the height h, by the angle that the incline does with the horizontal, as follows:

sin 8.29° = h /d ⇒ d= h / sin 8.29° = 46.2 m / sin 8.29° = 321 m

6 0

4 years ago

During a chemical reaction, some substances are completely consumed while others my not be. What is the substance that is comple

LUCKY_DIMON [66]

Answer:

It is Limiting Reactant

Explanation:

5 0

3 years ago

A 1000 Kg car approaches an intersection traveling north at 30 m/s . A 1250 Kg car approaches the same intersection traveling ea

Feliz [49]

Answer:

The final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

Explanation:

Taking north direction as positive y axis and east direction as positive x axis .

Given:

Mass of first car is, $m_1=1000\ kg$

Initial velocity of first car is, $u_1=30\vec{j}\ m/s$

Mass of second car is, $m_2=1250\ kg$

Initial velocity of second car is,

Let the combined final velocity after collision be 'v' m/s with as components of final velocity along east and north directions respectively.

Now, as the net external force is zero, momentum is conserved for the two car system along the east and north directions.

Conserving momentum along the east direction, we have:

Initial momentum = Final momentum

$m_1u_{1x}+m_2u_{2x}=(m_1+m_2)v_x\\\\0+1250\times 39=(1000+1250)v_x\\\\v_x=\frac{48750}{2250}\\\\v_x=\frac{65}{3} m/s$

There is no component of initial velocity for first car in east direction, as it is moving in the north direction. So,

Now, conserving momentum along the north direction, we have:

Initial momentum = Final momentum

$m_1u_{1y}+m_2u_{2y}=(m_1+m_2)v_y\\\\1000\times 30+0=(1000+1250)v_y\\\\v_y=\frac{30000}{2250}\\\\v_y=\frac{40}{3}\ m/s$

There is no component of initial velocity for second car in north direction, as it is moving in the east direction. So, $u_{2y}=0$ .

The magnitude of final velocity is given as:

$|\vec{v}|=\sqrt{(v_x)^2+(v_y)^2}\\\\|\vec{v}|=\sqrt{(\frac{65}{3})^2+(\frac{40}{3})^2}\\\\|\vec{v}|=\sqrt{\frac{5825}{9}}=25.44\ m/s$

The direction is given as:

$\theta=\tan^{-1}(\frac{v_y}{v_x})\\\\\theta=\tan^{-1}(\frac{\frac{40}{3}}{\frac{65}{3}})=31.61^\circ$

So, the final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

7 0

3 years ago

An object 4cm high is placed 15 cm from a convex lens of focal length 18cm. Draw a ray diagram and find the position, size, and

Nataly [62]

Answer:

what I don't no really????

3 0

3 years ago

If you float a piece of wood in a container half-full of water that rests on a weighing scale, the weight reading on the scale w

Alexeev081 [22]

If you float a piece of wood in a container half-full of water that rests on a weighing scale, the weight reading on the scale will increase.

<h3>What is Buoyancy?</h3>

Buoyancy is the force through your fluids or total or submerged bodies. Also known as Archimedes' theorem. The fluid of the direction on the body produces a resultant force but with the direction of the weight, with the opposite direction, upwards.

All material submerged in a liquid under the action of buoyancy, for this reason we have that the value on the scale will be increased with a system of a wood floating in water.

See more about Buoyancy at brainly.com/question/19168433

#SPJ12

5 0

2 years ago

Multiply these measurements, using significant digit rules: 1.27 kg x 9.8 m/s2 = kg ∙ m/s2