Answer:
7.35m/s²
Explanation:
From the question we are not told what to find but we can as well find the acceleration of the wagon.
According to newton second law of motion
Fm is the moving force = 410N
is the coefficient of friction = 0.18
m is the mass = 45kg
g is the acceleration dur to gravity = 9.8m/s²
a is the acceleration of the wagon
Substitute the given data into the equation ang get ax
Hence the acceleration of the wagon is 7.35m/s²
Answer:
The torque on the pulley, when the system is motionless is approximately 9.81 N·m
Explanation:
The given parameters are;
The mass of the object = 2 kg
The friction between the rope and the pulley = 0
The mass of the rope, = 0.5 kg
The mass of the pulley, = 0.01 kg
The radius of the pulley, r = 0.25 m
The torque on the pulley, τ = I·α = F × D
The torque on the pulley, when the system is motionless, τ = F × D
Where;
F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N
D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m
Therefore;
τ = 19.62 N × 0.5 m = 9.81 N·m
The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.