3 years ago

What is the current running through resistor five?

Physics

2 answers:

irga5000 [103]3 years ago

4 0

I believe it would be 3 amps.

AURORKA [14]3 years ago

3 0

I think it will be 3 amps.

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maw [93]

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Q=185.84C

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$Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C$

HOPE THIS HELPS!!

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