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Aleks04 [339]
3 years ago
13

A calorimeter contains 500 g of water at 25°C. You place a hand warmer containing 100 g of liquid sodium acetate (NaAC) inside t

he calorimeter. When the sodium acetate finishes crystallizing, the temperature of the water inside the calorimeter is 32.2°C. The specific heat of water is
4.18 J/g-°C. What is the enthalpy of fusion (ΔHf) of the sodium acetate? Show your work.
Chemistry
2 answers:
Free_Kalibri [48]3 years ago
6 0

Answer:The enthalpy of fusion (ΔH_f) of the sodium acetate is 12.344 kJ/mol.

Explanation:

Heat absorbed by the water: Q

Change in temperature of water,\Delta T=32.2^oC-25^oC=7.2^oC

Specific heat of water = 4.18 J/g°C

Mass of water = m= 500 g

Q=500 g\times 4.18 J/g ^oC\times 7.2^oC=15,048 J

\Delta H_f is the heat energy required to melt the one mole of substance.

When 200 g of sodium acetate crystallizes it gave 15,048 Joules of heat which was absorbed by the water in calorimeter.

NaAC(l)\rightarrow NaAC(s),\Delta H_f=?

Moles of NaAC=\frac{100 g}{82.03 g.mol}=1.2190 mol

\Delta H_f=\frac{15,048 J}{1.2190 mol}=12,344 J/mol=12.344 kJ/mol

The enthalpy of fusion (ΔH_f) of the sodium acetate is 12.344 kJ/mol.

antoniya [11.8K]3 years ago
3 0
The heat absorbed by the water is
Q = 500 (4.18) (32.2 - 25)
Q = 15048 J

The enthalpy of fusion of the sodium acetate is:
<span>ΔHf = Q / m
</span><span>ΔHf = 15048 / 100
</span>ΔHf = 150.48 J/g
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