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sladkih [1.3K]
3 years ago
13

A bullet is fired vertically upward from a gun with an initial velocity of 225 m/s. How high does the bullet go in meters? [Igno

re air resistance]
Physics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

h= 2582.9 m

Explanation:

bullet kinematics:  bullet moves with uniformly accelerated movement in freefall  

The negative sign in the equation indicates that the acceleration (g) is in the direction opposite to the movement of the  bullet.

v f₁²=v₀²-2g*h₁  Equation (1))

h: hight in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

Known data

v₀=  225 m/s

g= 9.8 m/s² : acceleration due to gravity

Problem development

When the  bulletl reaches the maximum height the final speed is equal to zero. vf=0

We replace data in the equation (1)

v f₁²=v₀²-2g*h₁

0 =  (225)²-2*9.8*h

2*9.8*h=(225)²

h= (225)²/ (2*9.8)

h= 2582.9 m

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Four engineers propose designs for door locks that are triggered by a sample of
sveta [45]

Question:

A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will

trigger a photosensor (a device that senses forms of light) that will open the lock."

B. Engineer B: "When the sample alpha decays, it only releases large amounts of heat.

This will trigger a thermometer that will open the lock."

C. Engineer C: "When the sample alpha decays, it will lose mass, This will trigger a scale

that will open the lock."

D. Engineer D: "When the sample alpha decays, it will give off negatively charged alpha

particles. Because alpha particles are electrons, they will complete a circuit that will

open the lock."

Answer:

The correct option is;

A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will trigger a photosensor ( a device that senses forms of light) that will open the lock"

Explanation:

Here, we note that in alpha decay (α-decay) there is an emission of an alpha particle or helium nucleus with the transformation of the parent element nucleus into that of a different element, having reduced mass and atomic numbers

Alpha particles are a form of ionizing radiation with a mass of 6.64 × 10⁻²⁷ kg and therefore they can be sensed by a photo sensor but will be slowly sensed by a scale.

7 0
3 years ago
An electron starts from rest near a negatively charged metal plate, and is accelerated towards a positive plate through a potent
Greeley [361]

Answer:

The magnetic field at the location is 5.375\times10^{-15}\ T

Explanation:

Given that,

Potential difference = 1320 V

Distance = 0.008 m

We need to calculate the velocity

Using conservation of energy

Electric potential energy lost = kinetic energy gained

qV=\dfrac{1}{2}mv^2

v^2=\dfrac{2qV}{m}

Put the value into the formula

v^2=\dfrac{2\times1.6\times10^{-19}\times1320}{9.1\times10^{-31}}

v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times1320}{9.1\times10^{-31}}}

v=2.15\times10^{7}\ m/s

We need to calculate the magnetic field at the location

Using formula of magnetic field

B=\dfrac{\mu qv}{4\pi r^2}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times1.6\times10^{-19}\times2.15\times10^{7}}{4\pi\times(0.008)^2}

B=5.375\times10^{-15}\ T

Hence, The magnetic field at the location is 5.375\times10^{-15}\ T

5 0
3 years ago
What is the final velocity of a body if it is moving with 13 m/s in 300 seconds and its acceleration is 30 m/s 2.
Nutka1998 [239]

Answer:

9013m/s

Explanation:

acceleration= v- u/ t

=> at = v-u

=> v = at + u

=> v =30*300+13

= 9013m/s

6 0
3 years ago
Karen drops a 2.0 kg rock from the top of a mountain. Determine the distance the rock travels after falling for 3 seconds assumi
aev [14]
Um...Is it 29.4m? I'm guessing, since, there's 3 seconds and it's at 9.8m/sec downward, so,

9.8 x 3 = 29.4m
8 0
3 years ago
Read 2 more answers
A stone is thrown straight up. While the stone is rising:
melamori03 [73]

Answer:

D. its acceleration is zero

Explanation:

Acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

In this scenario, a stone is thrown straight up. While the stone is rising its acceleration is zero because it's initial velocity is zero and it's until the stone reaches its highest point before the acceleration becomes constant and acting downward.

5 0
3 years ago
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