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3 years ago

If 25.4 grams of water react to form 2.8 grams of hydrogen, how many grams of oxygen must simultaneously be formed?

2 answers:

5 0

The mass of oxygen and hydrogen must be equal to the mass of the substance they create the water. So if the hydrogen is 2.8 g the oxygen must account for the rest of the mass. Basically just subtract 25.4-2.8=mass of oxygen

Natasha2012 [34]3 years ago

4 0

Answer:

There will be formed 22.6 grams O2

Explanation:

Step 1: Data given

Mass of 25.4 grams

Mass of hydrogen formed = 2.8 grams

Step 2: The balanced equation

2H2O(l) → 2H2(aq) + O2(aq)

For 2 moles H2O we'll have 2 moles hydrogen and 1 mol O2

Step 3: Calculate moles of H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 25.4 grmas / 18.02 g/mol

Moles H2O = 1.41 moles

Step 4: Calculate moles hydrogen formed

Moles H2 = 2.8 grams / 2.0 g/mol

Moles H2 = 1.4 moles

Step 5: Calculate moles of O2

For 2 mole of H2O reacted, there will be formed 1 mol of H2O

For 1.41 moles of H2O formed there will be formed 0.705moles O2.

Step 6: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 0.705* 32 g/mol

Mass O2 = 22.6 grams O2

There will be formed 22.6 grams O2

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Over the years, the thermite reaction has been used for years to welding railroad nails, in cendiary bombs, and to ignite solid

koban [17]

Answer:

A. 109.61 g of Fe₂O₃

B. 36.99 g of Al

C. Maximum mass of Al₂O₃ produced is 69.90 g

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ (s) + 2Al (s) → 2Fe (l) + Al₂O₃ (s)

Next, we shall determine the masses of Fe₂O₃ and Al that reacted and the masses of Fe and Al₂O₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe₂O₃ = (2×56) + (3×16)

= 112 + 48 = 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 2 × 27 = 54 g

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 2 × 56 = 112 g

Molar mass of Al₂O₃ = (2×27) + (3×16)

= 54 + 48 = 102 g/mol

Mass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g

SUMMARY:

From the balanced equation above,

160 g of Fe₂O₃ reacted with 54 g of Al to produce 112 g of Fe and 102 g of Al₂O₃

A. Determination of the mass of iron(III) oxide, Fe₂O₃, needed to produce 76.73 g of iron, Fe.

From the balanced equation above,

160 g of Fe₂O₃ reacted to produce 112 g of Fe.

Therefore, Xg of Fe₂O₃ will react to produce 76.73 g of Fe i.e

Xg of Fe₂O₃ = (160 × 76.73)/112

Xg of Fe₂O₃ = 109.61 g

Thus, 109.61 g of Fe₂O₃ is needed to produce 76.73 g of Fe.

B. Determination of the mass of aluminum, Al, to produce 76.72 g of iron, Fe.

From the balanced equation above,

54 g of Al reacted to produce 112 g of Fe.

Therefore, Xg of Al will react to produce 76.72 g of Fe i.e

Xg of Al = (54 × 76.72)/112

Xg of Al = 36.99 g

Thus, 36.99 g of Al is needed to produce 76.72 g of Fe.

C. Determination of the maximum mass of aluminum oxide, Al₂O₃, produced along with 76.75 g Fe.

We'll begin by calculating the mass of Fe₂O₃ needed to produce 76.75 g of Fe. This is illustrated below:

From the balanced equation above,

160 g of Fe₂O₃ reacted to produce 112 g of Fe.

Therefore, Xg of Fe₂O₃ will react to produce 76.75 g of Fe i.e

Xg of Fe₂O₃ = (160 × 76.75)/112

Xg of Fe₂O₃ = 109.64 g

Thus, 109.64 g of Fe₂O₃ is needed to produce 76.75 g of Fe.

Finally, we shall determine the maximum mass of Al₂O₃ produced along with 76.75 g Fe. this can be obtained as follow:

From the balanced equation above,

160 g of Fe₂O₃ reacted 102 g of Al₂O₃.

Therefore, 109.64 g of Fe₂O₃ will react to produce = (109.64 × 102)/160 = 69.90 g of Al₂O₃.

Thus, the maximum mass of Al₂O₃ produced is 69.90 g

6 0

3 years ago

Identify all statements that accurately describe the structure of the pyruvate dehydrogenase ( PDH ) complex.

Nostrana [21]

Answer:

The statements that correctly describes pyruvate dehydrogenase includes:

- Several copies each of E 1 and E 3 surround E 2.

-A regulatory kinase and phosphatase are part of the mammalian PDH complex.

-E 2 contains three domains.

Explanation:

Pyruvate dehydrogenase is a hydrolase key enzyme in glucose metabolism which converts pyruvate to acetyl- ChoA. It also forms a complex that catalyzes an irreversible reaction that is the entry point of pyruvate into the TCA cycle. Pyruvate dehydrogenase complex contains E1, E2 and E3 enzymes that transform pyruvate, NAD+, coenzyme A into acetyl-CoA, CO2, and NADH. Also, A regulatory kinase and phosphatase are part of the mammalian PDH complex and E 2 contains three domains.

5 0

3 years ago

Which 5.0-milliliter sample of NH3 will take the shape of and completely fill a closed 100.0-milliliter container?(1) NH3(s) (3)

antoniya [11.8K]

NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container.

5 0

3 years ago

In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is

GaryK [48]

Answer:

Attached below

Explanation:

Free energy of mixing = ΔGmix = Gf - Gi

attached below is the required derivation of the

<u>a) Molar Gibbs energy of mixing</u>

ΔGmix = Gf - Gi

hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )

<u>b) molar excess Gibbs energy of mixing</u>

Ni = chemical potential of gas

fi = Fugacity

N°i = Chemical potential of gas when Fugacity = 1

ΔG = RT In ( a2 / a1 )

4 0

3 years ago

Hello, please help me answer this it’s due tonight!

77julia77 [94]

Answer:

Explanation:

I think you should desigh a home. (you might say well thats obvi) I'm not done!

OK anyway desigh a house and think about ways to keep it warm. LIke a heater of fire place. ALso think about how you would get oxegen and air to live, since your on mars. Also use information about mars to help you!

- Hope it helps!

6 0

3 years ago