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Irina18 [472]
3 years ago
11

A gas in a rigid container at 25°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 a

tm. What is the new temperature of the gas? Use StartFraction P subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 over T subscript 2 EndFraction.. –44.2°C 32.6°C 115°C 388°C
Chemistry
2 answers:
zalisa [80]3 years ago
6 0

Answer:

Answer is c....115°C

Explanation:

Gay-Lussacs law says that pressure of a gas is the same as temperature when the volume is kept the same

P / T = k

where P - pressure , T - temperature in kelvin and k - constant

parameters for the first time are on the left side of the equation and parameters for the second instance are on the right side of the equation

T1 - 25 °C + 273 = 298 K

substiuting the values in the equation

T2 = 388 K

temperature in celcius - 388 K - 273 = 115 °C

Liono4ka [1.6K]3 years ago
5 0

Answer:

C. 115°C

Explanation:

Took test

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Answer:

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Explanation:

<u>Step 1: </u>data given

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Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

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initial temperature water T1 =22 °C

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<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

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maks197457 [2]

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