P1V1 = P2V2
P1 = 0.60 atm
V1 = 10.2 L
P2 = ?
V2 = 3.0 L
Solve for P2 —> P2 = P1V1/V2 = (0.60 atm)(10.2 L) / (3.0 L) = 2.04 atm
Explanation:
a) Barium
b) The metalloid in third period is Silicon
c) Group 4A (or IVA) of the periodic table includes the nonmetal carbon (C)
d) At this temperature, fluorine and chlorine are gases, bromine is a liquid, and iodine and astatine are solids.
e) osmium
f) chlorine (Cl, element 17) are a gas at room temperature, and is found as diatomic molecule (Cl2).
According to Clausius-Clayperon equation,

is the vapor pressure at boiling point = 760 torr
is the vapor pressure at T_{2} =638.43 torr
Temperature
Δ
Plugging in the values, we get

ln

Therefore, the boiling point of octane = 389 K - 273 = 
Answer:
I think that it is II and IV.
I'm not positive so don't count on it, but i'm bout to be in 11th grade and I remember my chemistry teacher showing us this video so there is a video on you tube where he explains in.
Explanation:
I'm sorry if this is useless, but lemme know what you get for the answer. Good Luck:)
Answer: oh i thought i knew it nvm im sorry love
Explanation: