Question

A toy car runs off the edge of a table that is 1.807 m high. The car lands 0.3012 m from the base of the table. How long does it take for the car to fall? The acceleration due to gravity is 9.8 m/s^2. Answer in units of s. What is the horizontal velocity of the car? Answer in units of m/s.

Answer 1

Answer:

a) $t=0.60 s$

b) $v_{ox} =0.5m/s$

Explanation:

From the exercise we have initial height and final X position

$y_{o}=1.807m$

$X=0.3012m$

a) From the concept of free falling objects we have that

$y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}$

Since the car runs off the edge of the table, that means the car is moving in x direction with $v_{oy}=0m/s$ and at the end of the motion $y=0m$

$0=1.807m-\frac{1}{2}(9.8)t^{2}$

Solving for t

t=± 0.6072 s

Since the time can not be negative, the answer is t=0.6072 s

b) To find the horizontal velocity of the car, we need to use the time that we just calculate

$X=v_{ox}t$

$v_{ox}=\frac{X}{t}=\frac{0.3012m}{0.6072s} =0.5m/s$