Answer:
0.84 m
Explanation:
Given in the y direction:
Δy = 0.60 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
0.60 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.35 s
Given in the x direction:
v₀ = 2.4 m/s
a = 0 m/s²
t = 0.35 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (2.4 m/s) (0.35 s) + ½ (0 m/s²) (0.35 s)²
Δx = 0.84 m
Answer:
The velocity of the Mr. miles is 17.14 m/s.
Explanation:
It is given that,
Mr. Miles zips down a water-slide starting at 15 m vertical distance up the scaffolding, h = 15 m
We need to find the velocity of the Mr. Miles at the bottom of the slide. It is a case of conservation of energy which states that the total energy of the system remains conserved. Let v is the velocity of the Mr. miles. So,
g is the acceleration due to gravity
v = 17.14 m/s
So, the velocity of the Mr. miles is 17.14 m/s. Hence, this is the required solution.
The Green work gymno means Naked
Adding thermal energy
Performing work on the system
Answer:
The gravitational potential energy of the two-sphere system just as B is released is
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Explanation:
The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as
U = -(GMm/d)
For our question,
Mass of object 1 = MA
Mass of object 2 = MB
Distance between them = x₁
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Hope this Helps!!!
