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lisov135 [29]
3 years ago
10

As an atom's nucleus gets larger the electric charges repelling the protons get larger. To compensate for this greater electric

charge the atom.
A.) needs more neutrons to gain enough nuclear binding forces to overcome
the repulsion.

B.) needs fewer neutrons to gain enough nuclear binding forces to overcome
the repulsion.

C.)needs more electrons to gain enough nuclear binding forces to overcome
the repulsion.

D.)needs fewer electrons to gain enough nuclear binding forces to overcome
the repulsion.
Physics
1 answer:
Nady [450]3 years ago
5 0

Answer:

b

Explanation:

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(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

<h3>Minimum force to be applied </h3>

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

  • μ(s) is coefficient of static friction
  • m is mass of the block
  • g is acceleration due to gravity

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

<h3>Acceleration of the block</h3>

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

Learn more about minimum force here: brainly.com/question/14353320

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4 0
2 years ago
The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance o
blsea [12.9K]

Answer:

F_f=840N

Explanation:

From the question we are told that

Weight of fireman W_f= 87.5kg

Pole distance D=4.10m

Final speed is V_f 1.75m/s

Generally the equation for velocity is mathematically represented as

v^2 = v_0^2 + 2 a d

Therefore Acceleration a

a'= v^2 / 2 d

a'= 0.21m/s^2

Generally the equation for Frictional force F_f is mathematically given as

F_f=m*a

F_f=m*(g-0.21)

F_f=87.5*(9.81-0.21)

Therefore

F_f=840N

6 0
3 years ago
Awnser these pls they r for middle schoolers lol
soldi70 [24.7K]

Answer:

Find the set of value of x Find the set of value of x which satisfy the inequality 2r2- 5x 2 18which satisfy the inequality 2r2- Find the set of value of x which satisfy the inequality 2r2- 5x 2 185x 2 18

8 0
3 years ago
(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel
sammy [17]

Answer:

Part a)

R_1 = 0.072 m

Part b)

R_2 = 0.036 m

Part c)

d = 0.072 m

Explanation:

Part a)

As we know that the radius of the charge particle in constant magnetic field is given by

R = \frac{mv}{qB}

now for single ionized we have

R_1 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(1.6 \times 10^{-19})(0.301)}

R_1 = 0.072 m

Part b)

Similarly for doubly ionized ion we will have the same equation

R = \frac{mv}{qB}

R_2 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(3.2 \times 10^{-19})(0.301)}

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Part c)

The distance between the two particles are half of the loop will be given as

d = 2(R_1 - R_2)

d = 2(0.072 - 0.036)

d = 0.072 m

6 0
3 years ago
A student says that a speed of 50 m/s is faster than a speed of 140 km/h because the number is bigger. What would you say to the
ladessa [460]

The units are not consistent - 1 m/s is not the same as 1 km/h.

First thing to do would be to convert from one unit of speed to the other, say km/h to m/s. There are 1000 meters (m) for every kilometer (km) and 3600 seconds (s) for every hour (h), so

1\,\dfrac{\mathrm{km}}{\mathrm h}\cdot\dfrac{10^3\,\mathrm m}{\mathrm{km}}\cdot\dfrac{\mathrm h}{3600\,\mathrm s}\approx0.278\,\dfrac{\mathrm m}{\mathrm s}

So in fact 1 km/h is about 4 times slower than 1 m/s.

4 0
3 years ago
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