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svetoff [14.1K]
4 years ago
11

Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)

Chemistry
1 answer:
andriy [413]4 years ago
6 0
20.7 g of Fe can be produced with 10.0g of Al

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Which is not a form of potential energy?<br><br> gravitational<br> chemical<br> elastic<br> thermal
Elena L [17]

Answer:Thermal Energy is not a form of potential energy

Explanation:

4 0
3 years ago
GOLF BALL PROPERTIES 1. Gabriel uses these numbers to find the density of the golf balls. Water has a density of 1.0 g/cm3. Whic
vagabundo [1.1K]

Answer:

ball B

Explanation:

6 0
3 years ago
Which two particles in an atom have the same mass ? protons and electrons or protons and neutrons
Sergio [31]
Protons and neutrons have about the same mass. Electrons are the smallest out of the three, in fact, protons weigh 1,836 times more than an electron.
4 0
3 years ago
1.00 M CaCl2 Density = 1.07 g/mL
Lesechka [4]

Explanation:

Molarity of solution = 1.00 M = 1.00 mol/L

In 1 L of solution 1.00 moles of calcium chloride is present.

Mass of solute or calcium chloride = m

m = 1 mol\times 111 g/mol = 111 g

Mass of solution = M

Volume of solution = V = 1L = 1000 mL

Density of solution , d= 1.07 g/mL

M=d\times V=1.07 g/mL\times 1000 mL=1,070 g

1) The value of %(m/M):

\frac{m}{M}\times 100=\frac{111 g}{1,070 g}\times 100=10.37\%

2) The value of %(m/V):

\frac{m}{V}\times 100=\frac{111 g}{1000 L}\times 100=11.1\%

Molality = \frac{\text{Moles of compound }}{\text{mass of solvent in kg}}

Normality=\frac{\text{Moles of compound }}{n\times \text{volume of solution in L}}

n = Equivalent mass

n = \frac{\text{molar mass of ion}}{\text{charge on an ion}}

3) Normality of calcium ions:

Moles of calcium ion = 1 mol (1 CaCl_2 mole has 1 mole of calcium ion)

n=\frac{40 g/mol}{2}=20

=\frac{1 mol}{20 g/mol\times 1L}=0.050 N

4) Normality of chlorine ions:

Moles of chlorine ion = 2 mol (1 CaCl_2 mole has 2 mole of chlorine ion)

n=\frac{35.5 g/mol}{1}=35.5

=\frac{2 mol}{35.5 g/mol\times 1L}=0.056 N

Moles of calcium chloride = 1.00 mol

Mass of solvent =  Mass of solution - mass of solute

= 1,070 g - 111 g = 959  g = 0.959 kg ( 1 g =0.001 kg)

5) Molality of the solution :

\frac{1 mol}{0.959 kg}=1.043 mol/kg

Moles of calcium chloride = n_1=1mol

Mass of solvent = 959 g

Moles of water = n_2=\frac{959 g}{18 g/mol}=53.28 mol

Mass of solvent = 959 g

6) Mole fraction of calcium chloride =

\chi_1=\frac{n_1}{n_1+n_2}=\frac{1mol}{1 mol+53.28 mol}=0.01842

7) Mole fraction of water =

\chi_2=\frac{n_2}{n_1+n_2}=\frac{53.28 mol}{1mol+53.28 mol}=0.9816

8) Mass of solution = m'

Volume of the solution= v = 100 mL

Density of solution = d = 1.07 g/mL

m'=d\times v=1.07 g/ml\times 100 g= 107 g

Mass of 100 mL of this solution 107 grams of solution.

9) Volume of solution = V = 100 mL

Mass of solution = M'' = 107 g

Mass of solute = m

The value of %(m/V) of solution = 11.1%

11.1\%=\frac{m}{100 mL}\times 100

m = 11.1 g

Mass of solvent = M''- m = 107 g -11.1 g = 95.9 g

95.9 grams of water was present in 100 mL of given solution.

3 0
3 years ago
If the hydroxide ion concentration of a solution is 3.26 x 10-6 M, is it an acidic or a basic solution?
sladkih [1.3K]

Answer: It is a basic solution with pH =8.51

Explanation:

We were given that hydroxide ion concentration [OH-] as 3.26 x 10-6 M

But We know thar

[OH-] [H+] = 1 × 10^-14

To get the Hydrogen ion [H+] concentration, we have that

[H+] = 1 × 10^-14 M/[OH-]

= 1 × 10^-14 M/3.26 x 10-6 M

    =  3.067 x 10^-9 M

But, pH = - log [H+]

Therefore,

pH = - log (3.067 x 10^-9)

pH=8.51

when  pH > 7, The solution is basic, therefore a solution with pH =8.51 is basic.

8 0
3 years ago
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