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Basile [38]
3 years ago
13

Why is thermal energy produced not generally usable to do work? A. Because the thermal energy dissipates too quickly and is not

concentrated enough to be used B. Because this energy is lost to the universe C. Because thermal energy is a form of energy that cannot be used to do any work D. Because thermal energy does not have the same equivalent to do work as other forms
Chemistry
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

A sounds like the best answer to me because thermal energy can cool very quickly if its hot

Explanation:

monitta3 years ago
3 0

Answer: Option a

Explanation: Thermal energy can be defined as using heat as a form of energy for doing work. It can be used for various processes.

But there is a problem associated with this energy, that is the thermal energy dessipiates very fastly and so it cannot be used as a form of energy for doing work.

It cools down very fastly and so it cannot be used as a source.

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Gravitational potential energy transforms into thermal energy.

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True or false when matter changes it’s state it is a physical change because it is the same substance the whole time.
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true

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What is the biological significance of the temperature at which the amylase catalyzed reaction
ipn [44]

Answer:

The biological significance is that it is the normal human body temperature and also the optimum temperature of the enzyme.

Explanation:

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Explain how the fire spreading from tree to tree provides a model for conduction.
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6 0
3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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