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amm1812
4 years ago
11

Positions of destructive interference on a standing wave are called .?

Physics
1 answer:
taurus [48]4 years ago
5 0

The answer is; nodes


A standing wave occurs when two waves with the same properties moving in the opposite direction, in the same media, interfere with one another. Nodes are points where the waves interact destructively causing an appearance of the wave standing still.  The opposite of nodes is antinodes where they are points of maximum displacement due to constructive destruction.


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A superball with a mass m = 61.6 g is dropped from a height h = [02]____________________ m. It hits the floor and then rebounds
aleksklad [387]

<em>There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem</em>

Answer:

(a) \Delta P=1.67 \ kg.m/s

(b) \Delta P=0.86\ m/s

Explanation:

<u>Change of Momentum</u>

The momentum of a given particle of mass m traveling at a speed v is given by

P=m.v

When this particle changes its speed to a value v', the new momentum is

P'=m.v'

The change of momentum is

\Delta P=m.v'-m.v

\Delta P=m.(v'-v)

Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.

(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:

U=m.g.h=0.0616\cdot 9.8\cdot 10 =6.0368\ J

This potential energy is transformed into kinetic energy just before the collision occurs, thus

\displaystyle \frac{1}{2}mv^2=6.0368

Solving for v

\displaystyle v=\sqrt{\frac{6.0368\cdot 2}{0.0616}}

v=-14\ m/s

This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is

h'=88.5\% (10)=8.85\ m

The potential energy reached by the ball at its rebound is

U'=m.g.h'=0.0616\cdot 9.8\cdot 8.85 =5.342568\ J

Thus the speed after the collision is

\displaystyle v'=\sqrt{\frac{5.342568\cdot 2}{0.0616}}

v'=13.17\ m/s

The change of momentum is

\Delta P=0.0616\cdot (13.17+14)

\Delta P=1.67 \ kg.m/s

(b) If the putty sticks to the floor, then v'=0

\Delta P=0.0616\cdot (0+14)

\Delta P=0.86\ m/s

3 0
4 years ago
To what pitch of the sound related?
jekas [21]
Hi friend
---------------
Your answer
---------------------

★ Pitch => It is the shrillness or coarseness of the sound.

Higher frequency = Shrill sound

Lower frequency = coarse sound

So, Final answer -

A. Frequency of sound waves

HOPE IT HELPS
6 0
4 years ago
Read 2 more answers
Which list places different units of matter in the correct sequence from largest to smallest
weqwewe [10]

Answer:

What do you mean?

6 0
3 years ago
Read 2 more answers
6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resi
Nonamiya [84]

\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
  • R is resistance

\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

5 0
3 years ago
Two carts, cart AA (mass 4.00 kgkg) and cart BB (mass 6.50 kgkg) move on a frictionless, horizontal track. Initially, cart BB is
tankabanditka [31]

Answer:

V{_a}'=-0.95m/s

Explanation:

From the question we are told that:

Mass of cart A m_a=4kg

Mass of cart B m_a=6.50kg

Speed of cart AA V-{a}=4.00

Generally the equation for velocity of  A after collision V{_a}' is mathematically given by

V_{a}'=\frac{M_a-M_b}{M_a+M+b} V_a

V{_a}'=\frac{4-6.5}{4+M6.5} *4

V{_a}'=\frac{4-6.5}{4+M6.5} *4

V{_a}'=-0.95m/s

3 0
3 years ago
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