Answer:
1) v = 7.70 10³ m/s
, 2) F = 115 N and 3) (F/W)% = 90.2%
Explanation:
1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal
F = ma.
F = G m M / r²
a = v² / r
G m M / r² = m v² / r
G M / r = v²
Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth
r = Re + 345 103
r = 6.37 10⁶ + 3.45 10⁵
r = 6.715 10⁶ m
Let's calculate the speed
v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)
v = 7.70 10³ m/s
The speed module is constant, so we can use the uniform motion relationships
v = d / t
The distance is the length of the circle
d = 2π r
d = 2π 6.715 106
d = 42.2 10⁶ m
Let's calculate the time
t = d / v
t = 42.2 10⁶ / 7.70 10³
t = 5.48 10³ s
2) Let's use the universal gravitation equation
F = G m M / r²
F = 6.67 10⁻¹¹ 13.0 5.98 10²⁴ /(6.715 10⁶)²
F = 11.5 10¹ N
F = 115 N
3) in this for we are asked the relationship is out with the weight of the body on earth
F / W = F / mg
F / W = 115 / (13.0 9.8)
F / W = 0.902
F / W% = 90.2%
Answer:
The terminal speed of this object is 12.6 m/s
Explanation:
It is given that,
Mass of the object, m = 80 kg
The magnitude of drag force is,
The terminal speed of an object is attained when the gravitational force is balanced by the gravitational force.
On solving the above quadratic equation, we get two values of v as :
v = 12.58 m/s
v = -15.58 m/s (not possible)
So, the terminal speed of this object is 12.6 m/s. Hence, this is the required solution.
Answer:
Explanation:
I am sorry but I am not able to see the question
Answer:
a. the density will not change
b. D' = 0.125 D
So, the density will change by a factor of 0.125
Explanation:
a.
Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.
Since, here the material remains the same.
<u>Therefore, the density will not change</u>
<u></u>
b.
Density = mass/Volume
D = m/V ------------ equation (1)
Now,
V = LWH ----------- equation (2)
Now, if each dimension increases by a factor of 2, the volume becomes:
V' = (2L)(2W)(2H)
V' = 8 LWH
using equation (2)
V' = 8 V
So, for constant mass, density becomes:
D' = m/V'
D' = m/8V
using equation (1)
D' = D/8
<u>D' = 0.125 D</u>
<u>So, the density will change by a factor of 0.125</u>
