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3 years ago

Summarize the difference in hydraulic and pneumatic systems.

Engineering

1 answer:

Naily [24]3 years ago

7 0

Answer:

The main difference between a pneumatic system and a hydraulic system lies in how the energy necessary to make these systems work is generated: thus, while in the pneumatic system this energy is generated through the compression of gases, in the hydraulic system the energy is obtained Through the insertion of pressurized fluids, such as water. Furthermore, hydraulic systems are closed circuits, where the water constantly circulates within the system; while in pneumatic systems the air that is compressed and used is constantly renewed.

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: During a heavy rainstorm, water from a parking lot completely fills an 18-in.- diameter, smooth, concrete storm sewer. If the

Montano1993 [528]

Answer

diameter of parking lot = 18 in

flowrate = 10 ft³/s

pressure drop = 100 ft

using general equation

$\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g}+Z_1 = \dfrac{P_2{\gamma} + \dfrac{v_2^2}{2g} + Z_2 +\dfrac{fLV^2}{2\rho D}$

$V = \dfrac{Q}{A} = \dfrac{10}{\dfrac{\pi}{4}(\dfrac{18}{12})^2} = 5.66\ ft/s$

$\Delta P = \gamma (Z_2-Z_1) +\dfrac{fLV^2}{2\rho D}$

taking f = 0.0185

at Z₁ = Z₂

$\Delta P = \dfrac{0.0185 \times 100\times 1.94\times 5.66^2}{2\dfrac{18}{12} (2)}$

ΔP = 0.266 psi

b) when flow is uphill z₂-z₁ = 2

$\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266$

$\Delta P= 1.13\ psi$

c) When flow is downhill z₂-z₁ = -2

$\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266$

$\Delta P=-0.601\ psi$

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3 years ago

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Answer:

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Answer:

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Define centrifugal pump. Give the construction and working of centrifugal pump.

fenix001 [56]

Centrifugal pump is a hydraulic machine which converts mechanical energy into hydraulic energy by the use of centrifugal force acting on the fluid. These are the most popular and commonly used type of pumps for the transfer of fluids from low level to high level.

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3 years ago

A 7-cm-external-diameter, 18-m-long hot-water pipe at 80°C is losing heat to the surrounding air at 5°C by natural convection wi

PilotLPTM [1.2K]

Answer:

The rate of heat loss from the pipe by natural convection is 4×10^-4 kW.

Explanation:

Q = kA(T1 - T2)/L

k is heat transfer coefficient = 25 W/m^2.°C

A is area of the pipe = πd^2/4 = 3.142 × 0.07^2/4 = 3.84895×10^-3 m^2

T1 - T2 is change in temperature = 80 - 5 = 75°C

L is length of the pipe = 18 m

Q = 25 × 3.85895×10^-3 × 75/18 = 0.4 W = 0.4/1000 = 4×10^-4 kW

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3 years ago