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3 years ago

How do you Convert kilograms to newtons?

Physics

1 answer:

REY [17]3 years ago

3 0

Answer:

To make a change between these two units of measurement, the formula to be used is kg x 9.807 = N which is the same conversion used automatically by the kg to N conversion calculator. As an example, 2kg = 19.6N and 5kg = 49N.

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You might be interested in

Sherlock Holmes examines a clue by holding his magnifying glass (with

Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

$\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm$

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

$M=-\frac{q}{p}=-\frac{-30}{10}=3$

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

8 0

4 years ago

An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 6.0 μC flows to the positive plate. The 4.0 V batte

Ugo [173]

Answer:

1 μC extra charge will be flow here

Explanation:

Given data

battery V1 = 4.0 V

flows Q1 = 6.0 μC

replace battery V2 = 7.0 V

to find out

what happen if we replace battery

solution

we apply here principal of capacitor

that is Q directly proportional voltage

so we say Q2/Q1 = V2/ V1

put all value here

Q2/Q1 = V2/ V1

Q2/6 = 7/ 6

Q2 = 7

so we see here 7 μC will be flow

and Q = Q2 - Q1 = 7 - 6 = 1 μC

so we also say that 1 μC extra charge will be flow here

5 0

4 years ago

Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.

LiRa [457]

Answer:

Explanation:

Given:

A = 589 J

D = 1 100 m

____________

F - ?

A = F·D

F = A / D = 589 / 1100 ≈ 0.54 N

5 0

1 year ago

Solids have definite shape and volume.<br> A. true<br> B. false

lesya [120]

In solid, atoms are compact. Hence they have definite shape and volume. Hence it is true.

5 0

4 years ago

Pilobolus is a genus of fungi commonly found on dung and known for launching its spores a large distance for a sporangiophore on

charle [14.2K]

1) The work done on the spores is $2.45\cdot 10^{-7}J$

2) The spores land 0.32 m away

Explanation:

According to the work-energy theorem, the work done on the ejected spores is equal to the change in kinetic energy of the spores:

$W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$

where

W is the work done

m is the mass of one spore

v is the final velocity

u is the initial velocity

For the spores in this problem, we have:

$m=10^{-8} kg$ is hte mass

u = 0 is the initial velocity (they start from rest)

v = 7.0 m/s is the final velocity

Substituting, we find the work done:

$W=\frac{1}{2}(10^{-8})(7.0)^2-0=2.45\cdot 10^{-7}J$

The motion of the spores is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by considering the vertical motion: this is a free fall motion, so we can use the suvat equation

$s=ut+\frac{1}{2}at^2$

where

s = 1 cm = 0.01 m is the vertical displacement (the height of the fungi)

u = 0 is the initial vertical velocity of the spore (it is ejected horizontally)

t is the time of flight

$a=g=10 m/s^2$ is the acceleration of gravity

Solving for t, we find:

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(0.01)}{10}}=0.045 s$

Now we can consider the horizontal uniform motion. Since the velocity is constant, the horizontal distance travelled is given by :

$d=v_x t$

where:

$v_x = 7.0 m/s$ is the horizontal velocity, which is constant

t = 0.045 s is the time of flight

Solving for d, we find:

$d=(7.0)(0.045)=0.32 m$

So, the spores land 0.32 m away.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0

4 years ago