Answer: The mass of aluminium sample is 55.4 gram
Explanation:
As we know that,
![m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
where,
= mass of aluminium = ?
= mass of water = 300.0 g
= final temperature = 
= temperature of aluminium = 
= temperature of water = 
= specific heat of aluminium = 
= specific heat of water = 
Now put all the given values in equation (1), we get
![-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=-%5Bm_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%5D%3D%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
![-[m_1\times 0.897\times (23.8-94.5)^0C]=[300.0g\times 4.184\times (23.8-21.0)]](https://tex.z-dn.net/?f=-%5Bm_1%5Ctimes%200.897%5Ctimes%20%2823.8-94.5%29%5E0C%5D%3D%5B300.0g%5Ctimes%204.184%5Ctimes%20%2823.8-21.0%29%5D)
Therefore, the mass of aluminium sample is 55.4 gram
Based on the concentration of the solutions, the increase in volume is as follows:
- the volume of the 20% (m/v) starch increases
- the volume of the 10% (m/v) albumin increases
- the volume of the 5% (m/v) sucrose increases
<h3>What is osmosis?</h3>
Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.
The movement of water molecules in the solution pairs is as follows:
- the volume of the 20% (m/v) starch increases because water moves in from the 10% (m/v) starch solution.
- the volume of the 10% (m/v) albumin increases because water moves in from the 2% (m/v) albumin
- the volume of the 5% (m/v) sucrose increases because water moves in from the 0.5% (m/v) sucrose.
Therefore, the increase in volume depends on the concentration ofvthe solutions.
Learn more about osmosis at: brainly.com/question/2625460
Answer:
A. 18
Explanation:
Sulfur number sixteen forms a negative
|ω・）
Answer:- B: 
is the right answer.
Solution:- The balanced equation is:
We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.
From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.
So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.
The complete set up looks as:
=
Hence, the right option is B: .
