Question

Write the chemical symbols for three different atoms or atomic cations with 27 electrons. Please help ASAP!

Answer 1

Answer: The chemical symbols for three different atoms or atomic cations with 27 electrons are $Co,Cu^{2+} \& Ni^{1+}$

Explanation:

An atom is neutral specie with equal number of electrons and protons in it.

Atomic number =  Number of protons = Number of electrons

Atomic number =- Number electrons = 27

The atom with 27 atomic number Cobalt that Co.

$[Co]=[Ar]3d^74s^2$

A cation is an ionic species which carry positive charge.When an atom looses an electron it forms cation.

Copper has atomic number of 29. When the copper atom looses 2 electrons it get converted into copper cation that is $Cu^{2+}$ with 27 electrons in its ion.

$[Cu]=[Ar]3d^{10}4s^1$

$[Cu^{2+}]=[Ar]3d^{9}4s^0$

Nickel has atomic number of 28.When the nickel atom looses 1 electron it get converted into nickel cation that is $Ni^{1+}$ with 27 electrons in its ion.

$[Ni]=[Ar]3d^{8}4s^2$

$[Ni^{1+}]=[Ar]3d^{8}4s^1$

So,the chemical symbols for three different atoms or atomic cations with 27 electrons are $Co,Cu^{2+} \& Ni^{1+}$