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kykrilka [37]
2 years ago
5

True or false? The empirical formula of a compound is the simplest formula that shows the numerical relationship of the elements

in the compound.
Chemistry
2 answers:
Alisiya [41]2 years ago
8 0

Answer:

True

Explanation:

the empirical formula usually shows us the atoms' symbols and then how much of them are present in this certain compound. For example there is H2O

Delicious77 [7]2 years ago
7 0

Answer:

True

Explanation:

I think it’s true because the empirical formula of a compound is actually the simplest formula that shows the numerical relationship of the elements in the compound.

hop that helps!

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Read the false statement.
liq [111]

Answer:

The second one is the correct statement.

Explanation:

An atom consists of a dense, heavy, positively charged central part called nucleus. It consists of neutrons and protons.

The electrons revolves around the nucleus in circular paths. These electrons are called planetary electrons because they can be compared to various planets revolving around the sun and the nucleus is compared with sun.

3 0
2 years ago
What is the voltage of a galvanic cell made with zinc (zn) and aluminum (al)?
bonufazy [111]
From the reduction standard potentials;
The emf of Zinc = -0.76 V
and the emf of Aluminium = -1.66 V
In a galvanic cell the component with lower standard reduction potential gets oxidized and that it is added to the anode compartment. 
Therefore. the voltage of a galvanic cell made with zinc and aluminium will be;
Voltage =Ered- Eoxd
             = -0.76 - (-1.66)
             = 0.9 V
6 0
3 years ago
Read 2 more answers
Gas particles do not have much energy of motion.<br><br> True or False?
QveST [7]
False is the answer
3 0
3 years ago
Read 2 more answers
24 POINTS!!!!!!!!!!
Oliga [24]
Your answer is going to be A, because it was shoved harder, it will go faster

8 0
3 years ago
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Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts
SOVA2 [1]

Answer:

\boxed{\text{Mg is the limiting reactant}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble the data in one place.

           2Mg + O₂ ⟶ 2MgO

n/mol:    2       5

Calculate the moles of MgO we can obtain from each reactant.

From Mg:  

The molar ratio of MgO:Mg is 2:2

\text{Moles of MgO} = \text{2 mol Mg} \times \dfrac{\text{2 mol MgO}}{\text{2 mol Mg}} = \text{2 mol MgO}

From O₂:  

The molar ratio of MgO:O₂ is 2:1.

\text{Moles of MgO} = \text{5 mol O}_{2} \times \dfrac{\text{2 mol MgO}}{\text{1 mol O}_{2}} = \text{10 mol MgO}\\\\\boxed{\textbf{Mg is the limiting reactant}} \text{ because it gives the smaller amount of MgO}

6 0
3 years ago
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