What is one thing in common with magnetic force?

A scientist studies a model of a widely accepted theory about the position of planets and sun. The model would most likely help

Troyanec [42]

If a scientist is studying a model that is a widely accepted theory about the position of planets and sun, the model would most likely help the scientist to understand facts that can't be easily observed. That will make the correct answer to be C.

4 0

3 years ago

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The diagram shows a position-time graph What is the displacement of the object

algol13

The object is moving, so at different times, it has different displacement. I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) . That's <em>-1m </em>.

5 0

3 years ago

if the instantaneous current in the circuit is giveen by I=3 sin theta amperes, the rms value of the current will be

Kisachek [45]

Answer:

$I_{rms}=2.12\ A$

Explanation:

Given that,

The instantaneous current in the circuit is giveen by :

$I=3\sin\theta\ A$

We need to find the rms value of the current.

The general equation of current is given by :

$I=I_o\sin\theta$

It means, $I_o=3\ A$

We know that,

$I_{rms}=\dfrac{I_o}{\sqrt2}\\\\=\dfrac{3}{\sqrt2}\\\\=2.12\ A$

So, the rms value of current is 2.12 A.

4 0

3 years ago

The following number - 0.050437 - written to TWO significant figures would be

Sophie [7]

Answer:

0.050000

Explanation:

your welcome :)

7 0

4 years ago

A hot air balloon rises at a constant speed of 13 meters/second relative to the air. There is a wind blowing eastwards at a spee

Airida [17]

Answer:

13.02 m/s the velocity and 86.92 degrees the direction relative to ground

Explanation:

We need to add velocities in vector addition to find the resultant velocity " $v$ " of the balloon (the 13 m/s and the 0.7 m/s).

The velocities are at 90 degrees from each other (one pointing up and the other to the East). Notice from the attached image that the resultant velocity vector (picture in red) is actually the hypotenuse of a right angle triangle.

So we use Pythagoras to find the length (magnitude) of the resultant velocity vector:

$v = \sqrt{13^2 +0.7^2} = 13.018832...$

we can round the answer to 13.02 m/s

Now we need to find the angle that this new vector makes with the ground by using the definition of tangent of an angle that relates the two quantities that we just added:

$tan (\theta) = 13/0.7 \\ \theta = arctan (\frac{13}{07} = 86.91781918...$

So we round it to 86.92 degrees

5 0

4 years ago